Python numbapro中的cuda代码错误

异常：由输入行11引起： 只能从全局、复数或数组中获取属性

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我是numbapro的新手，需要提示

@cuda.autotjit

将

foo（）

标记并编译为cuda内核。内存传输操作应该放在内核之外。它应该类似于以下代码：

import numpy
import numpy as np
from numbapro import cuda


@cuda.autojit
def foo(aryA, aryB,out):
    d_ary1 = cuda.to_device(aryA)
    d_ary2 = cuda.to_device(aryB)
    #dd = numpy.empty(10, dtype=np.int32)
    d_ary1.copy_to_host(out)


griddim = 1, 2
blockdim = 3, 4
aryA = numpy.arange(10, dtype=np.int32)
aryB = numpy.arange(10, dtype=np.int32)
out = numpy.empty(10, dtype=np.int32)

foo[griddim, blockdim](aryA, aryB,out)

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我建议新的NumbaPro用户查看中的示例。

您是否尝试过使用

numpy.zero

来创建

out

？只是好奇，numbapro不是付费产品吗？我想你也可以试着去买。

import numpy
from numbapro import cuda

@cuda.autojit
def foo(aryA, aryB ,out):
    # do something here
    i = cuda.threadIdx.x + cuda.blockIdx.x * cuda.blockDim.x
    out[i] = aryA[i] + aryB[i]

griddim = 1, 2
blockdim = 3, 4
aryA = numpy.arange(10, dtype=numpy.int32)
aryB = numpy.arange(10, dtype=numpy.int32)
out = numpy.empty(10, dtype=numpy.int32)

# transfer memory
d_ary1 = cuda.to_device(aryA)
d_ary2 = cuda.to_device(aryB)
d_out = cuda.device_array_like(aryA) # like numpy.empty_like() but for GPU
# launch kernel
foo[griddim, blockdim](aryA, aryB, d_out)

# transfer memory device to host
d_out.copy_to_host(out)

print out