Python csv文件到字典

我想从csv文件写入字典

但是：

一行中的第一个单词应该是关键字

行中的所有其他单词都应该是该键的独立值

到目前为止，我的代码是：

def coordinates(text):
    import csv
    reader = csv.reader(open(text))
    d = {}

    for row in reader:
        key = row[0]
        d[key] = row[1:]
    print(d)

coordinates('luchthavens2.csv')

使用此代码，行中的所有项都是我的字典中的键

谁能帮忙

编辑：

输入文件如下所示：

BIN，“巴米扬”，“巴米扬”，“阿富汗”，“阿富汗”，34.800000,67.816667701，“阿富汗”\N\N，1149361
英国夏令时，“波斯特”，“波斯特”，“阿富汗”，“阿富汗”，31.550000,64.366667701，“阿富汗”，11347201149361
CCN，“查克查兰”，“查克查兰”，“阿富汗”，“阿富汗”，34.533333,65.266667701，“阿富汗”，\N\N，1149361

全部来自名为Luchhavens2.csv的excel文件，文本位置为A1-A2-A3-etc

你可以在这里找到它：

输出：

{
'CCN,"Chakcharan","Chakcharan","Afghanistan","AF",34.533333,65.266667,701,"Afghanistan",\\N,\\N,1149361': [],
'BST,"Bost","Bost","Afghanistan","AF",31.550000,64.366667,701,"Afghanistan",\\N,1134720,1149361': [],
'BIN,"Bamiyan","Bamiyan","Afghanistan","AF",34.800000,67.816667,701,"Afghanistan",\\N,\\N,1149361': []
}

编辑：

---

我已将输入文件更改为文本文件，然后再次更改为csv文件。奇怪的是，这样做很有效，我可以毫无问题地阅读它。

如果您运行以下命令

import pprint
import csv


def coordinates(text):
    ret = {}
    with open(text, 'r') as fp:
        reader = csv.reader(fp)
        for row in reader:
            key = row.pop(0)
            ret[key] = row
    return ret


data = coordinates('data.csv')
pprint.pprint(data)

在以下文件中

$ cat data.csv 
AAA,"Blub",25.25
BBB,"Blob",27.27

然后你会得到

$ python stackoverflow.py 
{'AAA': ['Blub', '25.25'], 'BBB': ['Blob', '27.27']}

---

在输入文件中，引号被弄乱了

"BIN,""Bamiyan"",""Bamiyan"",""Afghanistan"",""AF"",34.800000,67.816667,701,""Afghanistan"",\N,\N,1149361"
"BST,""Bost"",""Bost"",""Afghanistan"",""AF"",31.550000,64.366667,701,""Afghanistan"",\N,1134720,1149361"
"CCN,""Chakcharan"",""Chakcharan"",""Afghanistan"",""AF"",34.533333,65.266667,701,""Afghanistan"",\N,\N,1149361"

应该是

"BIN","Bamiyan","Bamiyan","Afghanistan","AF",34.800000,67.816667,701,"Afghanistan",\N,\N,1149361
"BST","Bost","Bost","Afghanistan","AF",31.550000,64.366667,701,"Afghanistan",\N,1134720,1149361
"CCN","Chakcharan","Chakcharan","Afghanistan","AF",34.533333,65.266667,701,"Afghanistan",\N,\N,1149361

---

这将为您提供所需的输出。 您的数据不是正确的CSV格式

import csv
reader = csv.reader(open('luchthavens2.csv'))
d = {}

for row in reader:
    row = row[0].split(',')
    key = row[0]
    d[key] = row[1:]

您不需要CSV模块，因为您的数据不是正确的CSV

下面的代码将在没有CSV模块的情况下解决您的问题

d = dict()
with open('luchthavens2.csv') as fh:
    for row in fh:
        row = row.split(',')
        key = row[0]
        d[key] = row[1:]

---

你有什么样的数据可以给我们看吗？像

text

通常是什么样子的？像这样的东西（只有一行）：BIN，“Bamiyan”，“Bamiyan”，“Afghanistan”，“AF”，34.800000,67.816667701，“Afghanistan”，\N\N，1149361@Roelland如果行为：宾、“巴米扬”、“巴米扬”、“阿富汗”、“阿富汗”，34.800000,67.8166‌​67701，“阿富汗”‌​,\N、 \N，114936，输出是什么？将其上载到诸如expirebox之类的托管文件，然后在此处发布链接。如果您的数据不正确，则会出现不平衡的引用。修好它，你就应该很好/实际上我仍然有同样的问题！但可能与输入文件有关（请参阅帖子上的回复）。无论如何，谢谢你的努力！