Python 在列表中循环

我是python新手，一直在努力解决这个问题

a ='''arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/**abc**/888888888888888
arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/def/888888888888888
arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/ghi/888888888888888
arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/test/888888888888888'''

print(a)

如何循环遍历唯一的字符串

'arn:aws:elastic:us-west-:111111111111:loadbalancer/app/**abc**/888888888888888'

从列表中删除，而不在代码中指定，即使其位置发生变化？

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请解释！谢谢大家!

这段代码应该可以做到：

for line in a.split():
    print(line)

如果你想找到你提到的那一行：

for line in a.split():
    if line == 'arn:aws:elastic:us-west-:111111111111:loadbalancer/app/**abc**/888888888888888':
        print(line)

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您可以使用方法e

split

a ='''arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/**abc**/888888888888888
arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/def/888888888888888
arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/ghi/888888888888888
arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/test/888888888888888'''
for i, split_txt in enumerate(a.split()):
    print(f'{i+1}. string: {split_txt}')

输出

1. string: arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/**abc**/888888888888888
2. string: arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/def/888888888888888
3. string: arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/ghi/888888888888888
4. string: arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/test/888888888888888

如果你只想要第一行

a.split()[0]
'arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/**abc**/888888888888888'

如果你想找到不同图案的线条

for i in a.split():
    if '**abc**' in i:
        print(i)
arn:aws:elastic:us-west-1:111111111111:loadbalancer/app/**abc**/888888888888888

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哪根弦？在您的示例中，所有内容都是字符串？即使位置发生变化，每次输出都应该是字符串-'arn:aws:elastic:us west-'111111111:loadbalancer/app/**abc**/888888'