Python 将文件从表单上载到S3

Python 将文件从表单上载到S3,python,amazon-s3,flask,Python,Amazon S3,Flask,我是s3新手,正在尝试上载一些文件,但系统无法找到指定的文件:.jpg我理解这个问题。当文件保存在根目录下时,一切正常。但我不想保存文件。我想在表单中的操作之后直接上传它 def upload_to_s3(file_to_upload, s3_upload_folder): s3 = boto3.resource('s3', aws_access_key_id=app.config['ACCESS_KEY_ID'],

我是s3新手,正在尝试上载一些文件,但系统无法找到指定的文件:.jpg我理解这个问题。当文件保存在根目录下时,一切正常。但我不想保存文件。我想在
表单中的
操作之后直接上传它

def upload_to_s3(file_to_upload, s3_upload_folder):
    s3 = boto3.resource('s3',
                    aws_access_key_id=app.config['ACCESS_KEY_ID'],
                    aws_secret_access_key=app.config['SECRET_ACCESS_KEY'])

    s3.meta.client.upload_file(file_to_upload, app.config['BUCKET_NAME'], s3_upload_folder)


def _user_img_folder(form, file_name):
    username = session['name']
    vacation_name = slugify(form.test_name.data)
    directory = os.path.join(username, test_name)
    directory = os.path.join(UPLOAD_FOLDER, directory)
    return directory + '/' + file_name


@app.route('/post', methods=['GET', 'POST'])
def test():
    if _is_image():
        uploaded_images = request.files.getlist('photo')
        for image in uploaded_images:
            processed_image_name = _hash_image_name(image) # Returns hashed filename with extension
            directory = _user_img_folder(form, processed_image_name)
            upload_to_s3(str(processed_image_name), str(directory))
    return render_template('test.html', form=form, error=error)
谢谢你的帮助

编辑1:

{大量编辑}

{%extends'\u base.html%}
{%block content%}
{{form.csrf_token}
{{form.vacation_name(placeholder=“name Your vacation”)}

{{form.location(placeholder=“它在哪里?”)}
{{form.with_who(占位符='who was with you')}

{{form.description(placeholder=“告诉我们您的假期……或者不。”)}
{form.when(class=“datepicker”,placeholder=“when?”)}

{{form.photo(multiple=“multiple”)}
多恩 {%endblock%}
找到了答案:

我改变了主意

s3.meta.client.upload_file(file_to_upload, app.config['BUCKET_NAME'], s3_upload_folder)
致:


因此,诀窍是,您必须将文件放在磁盘上并提供
filepath
file\u-to\u-upload
,或者提供文件本身,正如我在回答中所演示的那样

更改为
methods=['POST']
@hjpotter92实际上它在那里,但我猜它忘了键入。你能发布你的
吗?@hjpotter92已发布^^
s3.meta.client.upload_file(file_to_upload, app.config['BUCKET_NAME'], s3_upload_folder)
s3.Object(app.config['BUCKET_NAME'], s3_upload_folder).put(Body=image)