Python可以'；由于目录错误，找不到我的文件

因此，我有一个函数，它可以刮取instagram数据并将喜欢的次数存储到字典中。我想我已经正确设置了该函数，但当我尝试运行print语句时，我不断遇到一个错误，即它找不到我要通过该函数运行的文件

这是我用来装载我的google驱动器并设置目录以存储我的json文件的代码。我在我的驱动器中验证了这一切都是正确的

# Mount data location. Do not edit this cell except as indicated.

# Be sure you have a folder in the root of your Google Drive called APRD6342/Data.
# Data files for the course should be uploaded to that folder.
from pathlib import Path
try:
    from google.colab import drive
    drive.mount('/content/drive')
    datadir = Path('drive/My Drive/APRD6342/Data') # you may edit this location ...
except ModuleNotFoundError:
    datadir = Path('../../Data') # ... but don't change this!!!


INSTAGRAM_DIR = datadir / 'instagram'

以下是我的功能：

def engagement(filename, follower_count):
    """Return the brand post engagement for the Instagram metadata file,
    filename, given follower_count as the number of Instagram followers for
    the brand.

    Returns a decimal engagement rate rounded to 4 decimal places. Python's
    standard `round` function should be used. E.g.:

    >>> engagement('instagram/volvocars.json', volvocars_follower_count)
    0.0125
    """
    with open(datadir / filename) as f:
        for line in f: #for each line in the file
            line_object = json.loads(line) 
            likes = line_object["GraphImages"]["edge_media_preview_like"]["count"] #find count

            if num in likes > 1:
                engagement.append(i) #add count to engagement
            comments = filename["GraphImages"]["edge_media_to_comment"]["count"] #find other count
            if num in comments > 1: 
                engagement.append(i) #add count
            engage_perc = sum(engagement)/follower_count #sum all counts and divide by the number of followers
    return engage_perc

以下是我尝试运行的打印语句和错误：

print('Honda:',
    as_percent(engagement(INSTAGRAM_DIR / 'honda.json', honda_follower_count)))


---> 12     with open(datadir / filename) as f:
     13         for line in f: #for each line in the file
     14             line_object = json.loads(line)

FileNotFoundError: [Errno 2] No such file or directory: 'drive/My Drive/APRD6342/Data/drive/My Drive/APRD6342/Data/instagram/honda.json'

---

我以前运行过装载代码，但出于某种原因，我的目录正在嵌套或其他什么。谢谢

使用调用函数时

print('Honda:',
    as_percent(engagement(INSTAGRAM_DIR / 'honda.json', honda_follower_count)))

您提供了完整路径，但在函数中再次添加了路径

 with open(datadir / filename) as f:

---

只传递子文件夹

instagram

和文件名。请注意文档字符串-他们提供了

'instagram/volvocars.json'

，因此您需要提供

'instagram/honda.json'

，以便能够找到一种不必使用jsonl文件而只使用json的方法。把一些语法弄混了

def engagement(filename, follower_count):
    """Return the brand post engagement for the Instagram metadata file,
    filename, given follower_count as the number of Instagram followers for
    the brand.

    Returns a decimal engagement rate rounded to 4 decimal places. Python's
    standard `round` function should be used. E.g.:

    >>> engagement('instagram/volvocars.json', volvocars_follower_count)
    0.0125
    """
    engagement = [] #set empty list for like counts
    data = filename #store filename to variable
    with open(data) as f: #save open file as outfile
        parse = json.load(f)
        for n in range(0,200):
            likes = parse["GraphImages"][n]["edge_media_preview_like"]["count"] #find count
            if likes > 1:
                    engagement.append(likes) #add count to engagement
            comments = parse["GraphImages"][n]["edge_media_to_comment"]["count"] #find other count
            if comments > 1: 
                    engagement.append(comments) #add count
            engage_perc = (sum(engagement)/len(range(0,200)))/follower_count #sum all counts and divide by the number of followers
        return round(engage_perc,4)

---

根据文档，尝试使用

os.path.abspath（）

。os.path.abspath（）返回路径名路径的规范化绝对版本，这听起来可能很奇怪，但它只是意味着此方法将路径名返回给作为参数传递给此函数的路径。