Python 将if-elseif语句转换为字典
我有以下代码用于对服务器进行RESTful调用:Python 将if-elseif语句转换为字典,python,design-patterns,dictionary,switch-statement,Python,Design Patterns,Dictionary,Switch Statement,我有以下代码用于对服务器进行RESTful调用: def request(self, request, account_id, user): if request is 'get_id': #Get user from id result = requests.get(api_root + "/accounts/" + account_id + "/users/" + user, headers=self.headers) elif reque
def request(self, request, account_id, user):
if request is 'get_id':
#Get user from id
result = requests.get(api_root + "/accounts/" + account_id + "/users/" + user, headers=self.headers)
elif request is 'get_username':
#Get user from username
result = requests.get(api_root + "/accounts/" + account_id + "/users?username=" + user, headers=self.headers)
elif request is 'get_email':
#Get user from username
result = requests.get(api_root + "/accounts/" + account_id + "/users?email=" + user, headers=self.headers)
elif request is 'post':
#Add user to new account
result = requests.post(api_root + '/accounts/' + account_id + '/users', data=json.dumps(user), headers=self.headers)
elif request is 'delete':
#Delete user from account
result = requests.delete(api_root + "/accounts/" + account_id + "/users/" + user, headers=self.headers)
#Throw exception if non-200 response
result.raise_for_status()
#Print request result / status
print "\nRequest " + request + " Result: " + result.text + "\nStatus: " + str(result.status_code)
return result
我知道这很难看,我想把它改成字典,比如:
def request(self, request, account_id, user):
url = api_root + "/accounts/" + account_id
function_dictionary = {}
function_dictionary['get_id'] = requests.get(url + "/users/" + user, headers=self.headers)
function_dictionary['get_username'] = requests.get(api_root + "/accounts/" + account_id + "/users?username=" + user, headers=self.headers)
function_dictionary['get_email'] = requests.get(api_root + "/accounts/" + account_id + "/users?email=" + user, headers=self.headers)
function_dictionary['delete'] = requests.delete(url + "/users/" + user, headers=self.headers)
function_dictionary['post'] = requests.post(url + '/users', data=json.dumps(user), headers=self.headers)
result = function_dictionary.get(request)
#Throw exception if non-200 response
result.raise_for_status()
return result
我仍然觉得我走错了方向。有人能告诉我Python中处理if/elseif语句的正确方法是什么吗
谢谢 使用
dict
替换if:elif:
循环肯定是Pythonic,但请注意,在您的示例中,您正在调用请求。对于存储在字典中的每个案例,获取
等,即字典值是这些调用的结果
另一种方法是在字典中分别存储函数和参数:
function_dict = {'get_id': (requests.get, # function
(url + "/users/" + user,), # tuple of arguments
{'headers': self.headers}), # dict of keyword args
...}
现在你可以使用
func, args, kwargs = function_dict[request]
result = func(*args, **kwargs)
另外,请注意,使用is
比较字符串是一个坏主意(尽管是这样);最好使用==
:
if request == 'get_id':
检查这里的元组:headers=self.headers。。。无效语法哇这很酷,只是几件事,
函数dict(request)
应该是函数dict[request]
对吗?对于我的post
请求,我应该如何包含data=json.dumps(user)
?我遇到语法错误,将更新我的问题。与其单独存储函数和参数,不如使用lambda
。这就是他们的目的@Tomcelic是的,应该是[]
;固定的json.dumps
是一个关键字参数,data
,因此应该在带有标题的字典中。