Python:If/Elif会两次问单个问题,而不是在回答之后继续问?
我向用户询问字典中的一组问题:Python:If/Elif会两次问单个问题,而不是在回答之后继续问?,python,function,if-statement,dictionary,return,Python,Function,If Statement,Dictionary,Return,我向用户询问字典中的一组问题: questions = { "strong": "Do ye like yer drinks strong? ", "salty": "Do ye like it with a salty tang? ", "bitter": "Are ye a lubber who likes it bitter? ", "sweet": "Would ye like a bit of sweetness with yer poison? ", "fruit
questions = {
"strong": "Do ye like yer drinks strong? ",
"salty": "Do ye like it with a salty tang? ",
"bitter": "Are ye a lubber who likes it bitter? ",
"sweet": "Would ye like a bit of sweetness with yer poison? ",
"fruity": "Are ye one for a fruity finish? "
}
ingredients = {
"strong": ["glug of rum", "slug of whiskey", "splash of gin"],
"salty": ["olive on a stick", "salt-dusted rim", "rasher of bacon"],
"bitter": ["shake of bitters", "splash of tonic", "twist of lemon peel"],
"sweet": ["sugar cube", "spoonful of honey", "splash of cola"],
"fruity": ["slice of orange", "dash of cassis", "cherry on top"]
}
beverage = {}
def drink():
"""Find out user preferences and assign to new dictionary"""
if raw_input(questions["strong"]).lower() == "yes":
beverage["strong"] = ingredients["strong"]
elif raw_input(questions["strong"]).lower() == "no":
return False
if raw_input(questions["salty"]).lower() == "yes":
beverage["salty"] = ingredients["salty"]
elif raw_input(questions["salty"]).lower() == "no":
return False
...
drink()
这些键与另一个字典关联:
questions = {
"strong": "Do ye like yer drinks strong? ",
"salty": "Do ye like it with a salty tang? ",
"bitter": "Are ye a lubber who likes it bitter? ",
"sweet": "Would ye like a bit of sweetness with yer poison? ",
"fruity": "Are ye one for a fruity finish? "
}
ingredients = {
"strong": ["glug of rum", "slug of whiskey", "splash of gin"],
"salty": ["olive on a stick", "salt-dusted rim", "rasher of bacon"],
"bitter": ["shake of bitters", "splash of tonic", "twist of lemon peel"],
"sweet": ["sugar cube", "spoonful of honey", "splash of cola"],
"fruity": ["slice of orange", "dash of cassis", "cherry on top"]
}
beverage = {}
def drink():
"""Find out user preferences and assign to new dictionary"""
if raw_input(questions["strong"]).lower() == "yes":
beverage["strong"] = ingredients["strong"]
elif raw_input(questions["strong"]).lower() == "no":
return False
if raw_input(questions["salty"]).lower() == "yes":
beverage["salty"] = ingredients["salty"]
elif raw_input(questions["salty"]).lower() == "no":
return False
...
drink()
我通过每个问题的“简单”if/elif集合向他们提问,并将他们的答案分配到新词典中:
questions = {
"strong": "Do ye like yer drinks strong? ",
"salty": "Do ye like it with a salty tang? ",
"bitter": "Are ye a lubber who likes it bitter? ",
"sweet": "Would ye like a bit of sweetness with yer poison? ",
"fruity": "Are ye one for a fruity finish? "
}
ingredients = {
"strong": ["glug of rum", "slug of whiskey", "splash of gin"],
"salty": ["olive on a stick", "salt-dusted rim", "rasher of bacon"],
"bitter": ["shake of bitters", "splash of tonic", "twist of lemon peel"],
"sweet": ["sugar cube", "spoonful of honey", "splash of cola"],
"fruity": ["slice of orange", "dash of cassis", "cherry on top"]
}
beverage = {}
def drink():
"""Find out user preferences and assign to new dictionary"""
if raw_input(questions["strong"]).lower() == "yes":
beverage["strong"] = ingredients["strong"]
elif raw_input(questions["strong"]).lower() == "no":
return False
if raw_input(questions["salty"]).lower() == "yes":
beverage["salty"] = ingredients["salty"]
elif raw_input(questions["salty"]).lower() == "no":
return False
...
drink()
最后,打印饮料:
print beverage
如果用户说“是”,一切正常
但是,如果用户回答“否”,则会再次询问第一个问题(可能是因为我使用raw_input()的if/elif结构),然后跳过完成脚本的所有其他问题
我如何构造它,以便如果用户对第一个问题说“不”,那么它会问下一个问题,而不是每个问题问两次
打印输出:
Do ye like yer drinks strong? yes
Do ye like it with a salty tang? no
Do ye like it with a salty tang? yes
Are ye a lubber who likes it bitter? no
Are ye a lubber who likes it bitter? yes
Would ye like a bit of sweetness with yer poison? no
Would ye like a bit of sweetness with yer poison? yes
Are ye one for a fruity finish? no
Are ye one for a fruity finish? yes
Yer cocktail is a made of a
['glug of rum']
出现此问题的原因是在每个
if..elif
案例中都会得到一个新的输入字符串。相反,您需要将输入分配给一个变量,并使用if..elif
检查输入是否正确
问两次问题:
if raw_input(questions["strong"]).lower() == "yes":
beverage["strong"] = ingredients["strong"]
elif raw_input(questions["strong"]).lower() == "no":
return False
问一次问题:
answer = raw_input(questions["strong"]).lower()
if answer == "yes":
beverage["strong"] = ingredients["strong"]
elif answer == "no":
return False
嗯,您的elif中还有另一个
原始输入
,它将读取一个新输入。将返回值赋给一个变量并使用它。