Python Tic Tac Toe check win功能不工作

所以我正在做一个tic-tac-toe程序，check-win函数不起作用，看起来它只是跳过了它，即使它是真的

这是我写的一种新方式，它不起作用

row_1 = board[0] == board[1] == board[2] != "-"
row_2 = board[3] == board[4] == board[5] != "-"
row_3 = board[6] == board[7] == board[8] != "-"

if row_1 or row_2 or row_3:
    if row_1 or row_2 or row_3 == char:
        status = True
        check = True
    elif row_1 or row_2 or row_3 == ai_char:
        status2 = True
        check = False

if board[0] == board[3] == board[6] == char:
    status = True
    check = True
if board[1] == board[4] == board[7] == char:
    status = True
    check = True
if board[2] == board[5] == board[8] == char:
    status = True
    check = True

if board[0] == board[3] == board[6] == ai_char:
    status2 = True
    check = False
if board[1] == board[4] == board[7] == ai_char:
    status2 = True
    check = False
if board[2] == board[5] == board[8] == ai_char:
    status2 = True
    check = False

这是我的老办法它不起作用

row_1 = board[0] == board[1] == board[2] != "-"
row_2 = board[3] == board[4] == board[5] != "-"
row_3 = board[6] == board[7] == board[8] != "-"

if row_1 or row_2 or row_3:
    if row_1 or row_2 or row_3 == char:
        status = True
        check = True
    elif row_1 or row_2 or row_3 == ai_char:
        status2 = True
        check = False

if board[0] == board[3] == board[6] == char:
    status = True
    check = True
if board[1] == board[4] == board[7] == char:
    status = True
    check = True
if board[2] == board[5] == board[8] == char:
    status = True
    check = True

if board[0] == board[3] == board[6] == ai_char:
    status2 = True
    check = False
if board[1] == board[4] == board[7] == ai_char:
    status2 = True
    check = False
if board[2] == board[5] == board[8] == ai_char:
    status2 = True
    check = False

这两种方法看起来都应该奏效，但都不行

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这就是全部代码

为什么不把它作为一个选项来简化呢

row1 = all(board[i] != '-' for i in [0,3,6])

您也可以尝试使用

row1 = all(board[i] != '-' for i in range(0,7,3))

上述代码的工作原理如下：

if board[0] != '-' and board[3] != '-' and board[6] != '-': 
    row1 = True
else:
    row1 = False

row_1_same = all(board[i] == board[i+1] for i in range(0,2))
row_2_same = all(board[i] == board[i+1] for i in range(3,5))
row_3_same = all(board[i] == board[i+1] for i in range(6,8))

在这种情况下，如果电路板[0]、电路板[3]、电路板[6]中的任何值等于“-”，则将导致False else True

在代码中，您正在检查整行。当您从0到8，其中行1=0,1,2，行2=3,4,5，行3=6,7,8时，这要容易得多

如果要检查每行中的值是否不是“-”，则此代码将起作用：

row_1_dash = all(board[i] != '-' for i in range(0,3))
row_2_dash = all(board[i] != '-' for i in range(3,6))
row_3_dash = all(board[i] != '-' for i in range(6,9))

如果要检查行中的每个值是否相同，则可以进行如下检查：

if board[0] != '-' and board[3] != '-' and board[6] != '-': 
    row1 = True
else:
    row1 = False

row_1_same = all(board[i] == board[i+1] for i in range(0,2))
row_2_same = all(board[i] == board[i+1] for i in range(3,5))
row_3_same = all(board[i] == board[i+1] for i in range(6,8))

您还可以使用以下方法检查值是否相同，是否不等于“-”：

row_1_win = all(board[i] == board[i+1] and board[i] != '-' for i in range(0,2))
row_2_win = all(board[i] == board[i+1] and board[i] != '-' for i in range(3,5))
row_3_win = all(board[i] == board[i+1] and board[i] != '-' for i in range(6,8))

使用这些选项，您可能可以减少代码，以确定玩家是否获胜

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如果您想了解完整的实现，请告诉我。这可能有助于您查看实施解决方案的选项。

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