Python 编解码器18/19战列舰
关于此代码,我有一些问题: 当我在板上输入数字1、2、3等时,它相应地显示为2、3、4。我希望它从1开始计数,而不是从0开始;我该怎么做? 如果我只是按回车键,它显示一个错误;我该如何改变这一点? 你能告诉我是否有一些错误,或者这个代码是否可以更容易地完成? 1:board[guess\u row][guess\u col]=X应该是board[guess\u row-1][guess\u col-1]=X 2:见下文:Python 编解码器18/19战列舰,python,Python,关于此代码,我有一些问题: 当我在板上输入数字1、2、3等时,它相应地显示为2、3、4。我希望它从1开始计数,而不是从0开始;我该怎么做? 如果我只是按回车键,它显示一个错误;我该如何改变这一点? 你能告诉我是否有一些错误,或者这个代码是否可以更容易地完成? 1:board[guess\u row][guess\u col]=X应该是board[guess\u row-1][guess\u col-1]=X 2:见下文: from random import randint board = [
from random import randint
board = []
for x in range(5):
board.append(["O"] * 5)
def print_board(board):
for row in board:
print " ".join(row)
print "Let's play Battleship!"
print_board(board)
def random_row(board):
return randint(0, len(board) - 1)
def random_col(board):
return randint(0, len(board) - 1)
ship_row = random_row(board)
ship_col = random_col(board)
print ship_row
print ship_col
# Everything from here on should go in your for loop!
# Be sure to indent four spaces!
for turn in range(4):
print "Turn", turn + 1# Print (turn + 1) here!
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))
if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sunk my battleship!"
break
else:
if guess_row not in range(5) or guess_col not in range(5):
print "Oops, that's not even in the ocean."
elif(board[guess_row][guess_col] == "X"):
print "You guessed that one already."
else:
print "You missed my battleship!"
board[guess_row][guess_col] = "X"
print_board(board)
if turn == 3:
print "Game Over"
3:而不是这个:
try:
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))
except ValueError:
print "Your gunners were asleep on the job!"
if turn == 3:
print "Game Over"
continue
使用列表理解:
board = []
for x in range(5):
board.append(["O"] * 5)
在Python2中,通常最好使用xrange而不是range。在Python3中使用range
除此之外,您的代码非常好而且简单明了
这是程序的完整代码。我没有安装Python2,所以我在中测试了它,它工作得非常好
board = [['O' for i in range(5)] for j in range(5)]
它向我展示了:File python,第32行ValueError除外:^SyntaxError:当我尝试执行您在2中所做的操作时,语法无效上一行是否有所有必要的右括号?语法错误通常需要更多的上下文。你能把数字3放在一个代码中吗?是的,我检查了所有的缩进,它仍然给我一个错误。我已经在我的答案中添加了程序的完整代码。请仔细地将其与代码进行比较,以确定错误在哪里。令人毛骨悚然的是,我已将第3点从您的问题列表中删除。这可以说超出了堆栈溢出的范围。一旦你让这段代码正常工作,我会邀请你发布一个工作版本,以获得一些关于如何使它尽可能好的指针。
from random import randint
board = [['O' for i in range(5)] for j in range(5)]
def print_board(board):
for row in board:
print " ".join(row)
print "Let's play Battleship!"
print_board(board)
def random_row(board):
return randint(0, len(board) - 1)
def random_col(board):
return randint(0, len(board) - 1)
ship_row = random_row(board)
ship_col = random_col(board)
print ship_row
print ship_col
# Everything from here on should go in your for loop!
# Be sure to indent four spaces!
for turn in range(4):
print "Turn", turn + 1# Print (turn + 1) here!
try:
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))
except ValueError:
print "Your gunners were asleep on the job!"
if turn == 3:
print "Game Over"
continue
if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sunk my battleship!"
break
else:
if guess_row not in range(5) or guess_col not in range(5):
print "Oops, that's not even in the ocean."
elif(board[guess_row][guess_col] == "X"):
print "You guessed that one already."
else:
print "You missed my battleship!"
board[guess_row-1][guess_col-1] = "X"
print_board(board)
if turn == 3:
print "Game Over"