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Python 向现有数据帧添加行的最快方法_Python_Pandas - Fatal编程技术网

Python 向现有数据帧添加行的最快方法

Python 向现有数据帧添加行的最快方法,python,pandas,Python,Pandas,我目前正试图在现有csv的基础上创建一个新的csv 我找不到基于现有数据帧值设置数据帧值的更快方法 import pandas import sys import numpy import time # path to file as argument path = sys.argv[1] df = pandas.read_csv(path, sep = "\t") # only care about lines with response_time df = df[pandas.notnu

我目前正试图在现有csv的基础上创建一个新的csv

我找不到基于现有数据帧值设置数据帧值的更快方法

import pandas
import sys
import numpy
import time

# path to file as argument
path = sys.argv[1]
df = pandas.read_csv(path, sep = "\t")

# only care about lines with response_time
df = df[pandas.notnull(df['response_time'])]

# new empty dataframe
new_df = pandas.DataFrame(index = df["datetime"])    

# new_df needs to have datetime as index 
# and columns based on a combination 
# of 2 columns name from previous dataframe 
# (there are only 10 differents combinations)
# and response_time as values, so there will be lots of 
# blank cells but I don't care
for i, row in df.iterrows():
    start = time.time()
    new_df.set_value(row["datetime"], row["name"] + "-" + row["type"], row["response_time"])
    print(i, time.time() - start)
原始数据帧是:

                     datetime           name   type  response_time
0  2018-12-18T00:00:00.500829    HSS_ANDROID  audio        0.02430
1  2018-12-18T00:00:00.509108    HSS_ANDROID  video        0.02537
2  2018-12-18T00:00:01.816758       HSS_TEST  audio        0.03958
3  2018-12-18T00:00:01.819865       HSS_TEST  video        0.03596
4  2018-12-18T00:00:01.825054  HSS_ANDROID_2  audio        0.02590
5  2018-12-18T00:00:01.842974  HSS_ANDROID_2  video        0.03643
6  2018-12-18T00:00:02.492477    HSS_ANDROID  audio        0.01575
7  2018-12-18T00:00:02.509231    HSS_ANDROID  video        0.02870
8  2018-12-18T00:00:03.788196       HSS_TEST  audio        0.01666
9  2018-12-18T00:00:03.807682       HSS_TEST  video        0.02975
新的_df将如下所示:

我每圈7毫秒

处理(仅?)400000行数据帧需要很长时间。如何加快速度?

事实上,使用将实现您想要的功能,例如:

import pandas as pd
new_df = pd.pivot(df.datetime, df.name + '-' + df.type, df.response_time)
print (new_df.head())
                           HSS_ANDROID-audio  HSS_ANDROID-video  \
datetime                                                           
2018-12-18T00:00:00.500829             0.0243                NaN   
2018-12-18T00:00:00.509108                NaN            0.02537   
2018-12-18T00:00:01.816758                NaN                NaN   
2018-12-18T00:00:01.819865                NaN                NaN   
2018-12-18T00:00:01.825054                NaN                NaN   

                            HSS_ANDROID_2-audio  HSS_ANDROID_2-video  \
datetime                                                               
2018-12-18T00:00:00.500829                  NaN                  NaN   
2018-12-18T00:00:00.509108                  NaN                  NaN   
2018-12-18T00:00:01.816758                  NaN                  NaN   
2018-12-18T00:00:01.819865                  NaN                  NaN   
2018-12-18T00:00:01.825054               0.0259                  NaN   

                            HSS_TEST-audio  HSS_TEST-video  
datetime                                                    
2018-12-18T00:00:00.500829             NaN             NaN  
2018-12-18T00:00:00.509108             NaN             NaN  
2018-12-18T00:00:01.816758         0.03958             NaN  
2018-12-18T00:00:01.819865             NaN         0.03596  
2018-12-18T00:00:01.825054             NaN             NaN  
要不具有
NaN
,您可以将其与任何想要的值一起使用,例如:

new_df = pd.pivot(df.datetime, df.name +'-'+df.type, df.response_time).fillna(0)

您还可以使用
取消堆叠
作为另一个选项

new = df.set_index(['type','name', 'datetime']).unstack([0,1])
new.columns = ['{}-{}'.format(z,y) for x,y,z, in new.columns]
使用
f-strings
将比
格式快一点:


new.columns=[f'{z}-{y}代表x,y,z,在new.columns]

是否要复制数据帧?可以使用loc。对不起,我没有时间给你打一个好的例子。不过,这里有一些文档:以文本而不是图片的形式提供一些输入数据。使用可能是解决您试图解决的问题的一种方法do@MohitMotwani不,我不想复制一个数据帧,我们需要看到原始数据帧(df),你能做
df.head(10)吗。。。谢谢