Python 遍历文件&；读取要保存到csv的内容

我有如下目录结构：

`~/ansible-environments/aws/random_name_1/inventory/group_vars/all`
~/ansible-environments/aws/random_name_2/inventory/group_vars/all`
~/ansible-environments/aws/random_name_3/inventory/group_vars/all`

所有文件看起来像

`
alias: bloodyhell
vendor_id: 42
isv_secret_key: "{{ vendor_id }}-SecretKey"
isv_secret_key_id: "{{ vendor_id }}-SecretKeyId"
products: rms_scl
LMIT: 80
sales_order_no: 'RMS_BSO_8182'
`

我需要编写一个python脚本，它可以遍历此目录结构，然后提取别名、LMIT、产品，并将内容写入csv文件，如下所示：

``` 别名、LMIT、产品 布雷德希尔，80岁，皇家海军陆战队

。 . 等等 . ``` 我编写了如下代码：

import os
import sys
rootdir='/home/ubuntu/ansible-environments/aws'
#print "aa"
for root, subdirs, files in os.walk(rootdir):
#  print "a"
  for j in subdirs:
       try:
           mypath = rootdir + '/' + j + '/' + 'inventory/group_vars/all'
           print  mypath
           fo = open(mypath, 'r')
           f = fo.readlines()
           #    print f
           for line in f:
               # print line
               if ('isv_alias' in line or 'LMID' in line or 'products' in line):
                   path = rootdir + '/' + 'list.csv'
                   fi = open(path, 'a')
                   fi.write(line)
                   fi.close()
           fo.close()
       except:
           pass

这就是我得到的结果：

`isv_别名：“血腥地狱”^M
isv_别名：血腥地狱
产品:rms_scl
LMID:80
isv_别名：rmstest2
产品:rms_scl
LMID:80
isv_别名：Surigatest
产品：rms_ems_托管
LMID:26

有人能帮我修一下吗