Python 在不展平的情况下子集字符串列表

我有以下清单：

A = [['Computer Science', 'Gender- Male', 'Race Ethnicity- Hispanic', 'Race Ethnicity- White'],
    ['Computer Science', 'Gender- Female', 'Race Ethnicity- White'],
    ['History', 'Gender-Female', 'Race Ethnicity- Black'],
    ['Mechanical Engineering', 'Geder- Male', 'Race Ethnicity- American Indian or Alaskan Native', 'Race Ethnicity- Hispanic']]

我只想保留涉及种族和民族的因素。这就是我想要的结局：

B = [['Race Ethnicity- Hispanic', 'Race Ethnicity- White'],
    ['Race Ethnicity- White'],
    ['Race Ethnicity- Black'],
    ['Race Ethnicity- American Indian or Alaskan Native', 'Race Ethnicity- Hispanic']]

下面的类型可以工作，但不保留列表结构的列表

[y for x in test for y in x if "Race Ethnicity" in y]

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我该怎么做呢？

你很接近了。尝试：

[[y for y in x if 'Race' in y] for x in test]

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嵌套列表理解将保持您的二维性。

您非常接近。尝试：

[[y for y in x if 'Race' in y] for x in test]

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嵌套列表理解将保持您的二维性。

因为您希望结果是列表列表，您应该尝试使用

[[item for item in sublist if（condition）]形式的命令，用于biglist中的sublist]

。试试这个：

A = [['Computer Science', 'Gender- Male', 'Race Ethnicity- Hispanic', 'Race Ethnicity- White'],
    ['Computer Science', 'Gender- Female', 'Race Ethnicity- White'],
    ['History', 'Gender-Female', 'Race Ethnicity- Black'],
    ['Mechanical Engineering', 'Geder- Male', 'Race Ethnicity- American Indian or Alaskan Native', 'Race Ethnicity- Hispanic']]

print([ [info for info in student if "Race Ethnicity" in info] for student in A ])

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由于您希望结果是一个列表列表，因此应尝试使用

[[item for item in sublist if（condition）]形式的命令，用于biglist中的子列表]

。试试这个：

A = [['Computer Science', 'Gender- Male', 'Race Ethnicity- Hispanic', 'Race Ethnicity- White'],
    ['Computer Science', 'Gender- Female', 'Race Ethnicity- White'],
    ['History', 'Gender-Female', 'Race Ethnicity- Black'],
    ['Mechanical Engineering', 'Geder- Male', 'Race Ethnicity- American Indian or Alaskan Native', 'Race Ethnicity- Hispanic']]

print([ [info for info in student if "Race Ethnicity" in info] for student in A ])

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您还可以在listcomp中使用函数

filter（）

：

[list(filter(lambda x: x.startswith('Race'), i)) for i in A]

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您还可以在listcomp中使用函数

filter（）

：

[list(filter(lambda x: x.startswith('Race'), i)) for i in A]