Python如何循环列表并使用列表值的每2个作为参数?
我有两个嵌套列表:Python如何循环列表并使用列表值的每2个作为参数?,python,python-3.x,dictionary,Python,Python 3.x,Dictionary,我有两个嵌套列表: grouped1 ={'LabelStat': { 'Carrier': ['1', '1'], 'FormID': ['0201', '0430']}, 'McAfee': {'DatDate': 'Not Available', ' DatVersion': 'Not Available'} }
grouped1 ={'LabelStat': { 'Carrier': ['1', '1'],
'FormID': ['0201', '0430']},
'McAfee': {'DatDate': 'Not Available',
' DatVersion': 'Not Available'}
}
grouped2 ={'LabelStat': {'Carrier': ['2', '2'],
'FormID': ['10201', '10430']},
'McAfee': {'DatDate': 'Available',
'DatVersion': 'Available',}
}
一个函数将合并这两个列表,它可以工作:
from collections import defaultdict
import re
def merge(*d):
v = defaultdict(list)
for i in d:
for a, b in i.items():
v[re.sub('^\s+', '', a)].append(b)
return {a:merge(*b) if all(isinstance(j, dict) for j in b)
else [i for j in b for i in (j if isinstance(j, list) else [j])]
for a, b in v.items()}
print(merge(grouped1, grouped2))
此函数的输出为:
om_grouped = {
'LabelStat': {'Carrier': ['1', '1','2','2'],
'FormID': ['0201', '0430','10201', '10430']}
'McAfee': {'DatDate': ['Not Available','Available']
'DatVersion': ['Not Available','Available']}
}
所以现在字典的数量是固定的,在上面我有2个,但是如果数字是动态的,比如我也有grouped3:
grouped3 ={'LabelStat': {'Carrier': ['3', '3'],
'FormID': ['102013', '104303']},
'McAfee': {'DatDate': 'Available3',
'DatVersion': 'Available3',}
}
我的问题是如何修改合并函数以使参数动态
我试着把所有的字典都列在一个列表中:
dic_list = [grouped1,grouped2,grouped3]
然后使用映射功能:
combin = map(merge,d_list)
print(combin)
for i in combin:
print(i)
但问题是:
<map object at 0x000001AC43E7AF40>
{'LabelStat': {'Carrier': ['1', '1'], 'FormID': ['0201', '0430']}, 'McAfee': {'DatDate': ['Not Available'], 'DatVersion': ['Not Available']}}
{'LabelStat': {'Carrier': ['2', '2'], 'FormID': ['10201', '10430']}, 'McAfee': {'DatDate': ['Available'], 'DatVersion': ['Available']}}
{'LabelStat': {'Carrier': ['3', '3'], 'FormID': ['102013', '104303']}, 'McAfee': {'DatDate': ['Available3'], 'DatVersion': ['Available3']}}
{'LabelStat':{'Carrier':['1','1'],'FormID':['0201','0430']},'McAfee':{'DatDate':['Not Available'],'DatVersion':['Not Available']}
{'LabelStat':{'Carrier':['2','2'],'FormID':['10201','10430']},'McAfee':{'DatDate':['Available'],'DatVersion':['Available']}
{'LabelStat':{'Carrier':['3','3'],'FormID':['102013','104303']},'McAfee':{'DatDate':['Available3'],'DatVersion':['Available3']}
只需使用解包:
r = merge(*dic_list)
输出:
{'LabelStat': {'Carrier': ['1', '1', '2', '2', '3', '3'], 'FormID': ['0201', '0430', '10201', '10430', '102013', '104303']}, 'McAfee': {'DatDate': ['Not Available', 'Available', 'Available3'], 'DatVersion': ['Not Available', 'Available', 'Available3']}}
这回答了你的问题吗?很好用,非常感谢!!!真棒@威廉很乐意帮忙!