python django如何在单击单个员工的姓名时仅显示其相关信息

我是python django的新手，试图创建一个员工记录项目，在django管理站点上我添加了一些员工及其信息，在django站点上，我有一个针对单个员工的超链接，但是当我单击个人名称时，下一页显示的是所有员工信息，而不是特定的信息，我怎样才能只显示我单击的员工的信息？请帮忙，谢谢

models.py

from django.db import models
import datetime

class Employee(models.Model):
    '''An employee's information.'''
    full_name = models.CharField(max_length=100)
    address = models.CharField(max_length=100)
    city = models.CharField(max_length=100)
    state = models.CharField(max_length=100)
    zip = models.CharField(max_length=100)
    hire_date = models.DateField(default=datetime.date.today)

    def __str__(self):
        '''Return a string representation of the model.'''
        return self.full_name
        return self.address
        return self.city
        return self.state
        return self.zip
        return self.hire_date

views.py

from django.shortcuts import render
from .models import Employee

def index(request):
    '''The home page for employee_record.'''
    return render(request, 'employee_records/base.html')

def employees(request):
    '''Shows all employees'''
    employees = Employee.objects.order_by('full_name')
    context = {'employees': employees}
    return render(request, 'employee_records/employees.html', context)

def employee(request, employee_id):
    '''Show a single employee and all his records.'''
    employee = Employee.objects.get(id=employee_id)
    objects = Employee.objects.all
    context = {'employee': employee, 'objects': objects}
    return render(request, 'employee_records/employee.html', context)

url.py

'''Defines URL patterns for employee_records.'''
from django.urls import path
from . import views

app_name = 'employee_records'
urlpatterns = [
    # Home page
    path('', views.employees, name='employees'),

    # Detail page for a single employee
    path('employees/<int:employee_id>/', views.employee, name='employee'),
]

''定义员工记录的URL模式''
从django.url导入路径
从…起导入视图
应用程序名称='员工记录'
URL模式=[
#主页
路径（“”，views.employees，name='employees'），
#单个员工的详细信息页面
路径（'employees/'，views.employee，name='employee'），
]

base.html

<p>
  <a href="{% url 'employee_records:employees' %}">Employee-Record</a>
</p>

{% block content %}{% endblock content %}

{%block content%}{%endblock content%}

employees.py

{% extends 'employee_records/base.html' %}

{% block content %}

  <ul>
    {% for employee in employees %}   

     <li>
        <a href="{% url 'employee_records:employee' employee.id %}">{{ employee }}</a>
     </li>

    {% empty %}

    {% endfor %}
  </ul>

{% endblock content %}

{%extends'employee_records/base.html%}
{%block content%}

{employees%%中的员工为%s}


{%empty%}
{%endfor%}

{%endblock内容%}

employee.html

{% extends 'employee_records/employees.html' %}

{% block content %}

  <p>{{ employee }}

    {% for object in objects %}
      <li>{{ object.full_name }}</li>
      <li>{{ object.address }}</li>
      <li>{{ object.city }}</li>
      <li>{{ object.state }}</li>
      <li>{{ object.zip }}</li>
      <li>{{ object.hire_date }}</li>

    {% empty %}

      <li>There are no records for this employee yet.</li>

    {% endfor %}
  </p>

{% endblock content %}

{%extends'employee_records/employees.html%}
{%block content%}
{{employee}}
{对象%中的对象的%}
{{object.full_name}
{{object.address}}
{{object.city}
{{object.state}
{{object.zip}}
{{object.hire_date}
{%empty%}
还没有此员工的记录
{%endfor%}

{%endblock内容%}

models.py
#您应该只有一个return语句
员工类别（models.Model）：
“员工信息”
全名=models.CharField（最大长度=100）
地址=models.CharField（最大长度=100）
城市=型号.CharField（最大长度=100）
state=models.CharField（最大长度=100）
zip=models.CharField（最大长度=100）
hire\u date=models.DateField（默认值为datetime.date.today）
定义（自我）：
''返回模型的字符串表示形式''
返回self.full\u名称
views.py
#你必须改变员工的职能
def员工（请求、员工id）：
''显示单个员工''
尝试：
employee=employee.objects.get（id=employee\u id）
除Employee.DoesNotExist外：
雇员=无
上下文={'employee'：employee}
返回呈现（请求'employee_records/employee.html'，上下文）
employee.html
{%extends'employee_records/employees.html%}
{%block content%}
{%if employee%}

{{employee.full_name}
{{employee.address}
{{employee.city}
{{employee.state}
{{employee.zip}
{{雇员.雇用日期}

{%endif%}
{%endblock内容%}

实现它的另一种方法是使用内置的get\u object\u或\u 404方法

个人观点

---

您正在使用

{%for objects%}

对所有员工进行显式检查。

models.py

# you should have only one return statement

class Employee(models.Model):
    '''An employee's information.'''
    full_name = models.CharField(max_length=100)
    address = models.CharField(max_length=100)
    city = models.CharField(max_length=100)
    state = models.CharField(max_length=100)
    zip = models.CharField(max_length=100)
    hire_date = models.DateField(default=datetime.date.today)

    def __str__(self):
        '''Return a string representation of the model.'''
        return self.full_name


views.py

# you have to change employee function

def employee(request, employee_id):
    '''Show a single employee'''
    try:
        employee = Employee.objects.get(id=employee_id)
    except Employee.DoesNotExist:
        employee = None

    context = {'employee': employee}
    return render(request, 'employee_records/employee.html', context)



employee.html

{% extends 'employee_records/employees.html' %}

{% block content %}

{% if employee %}
    <ul>
        <li>{{ employee.full_name}}</li>
        <li>{{ employee.address}}</li>
        <li>{{ employee.city}}</li>
        <li>{{ employee.state}}</li>
        <li>{{ employee.zip}}</li>
        <li>{{ employee.hire_date}}</li>
    </ul>
{% endif %}

{% endblock content %}

from django.shortcuts import get_object_or_404

def employee(request, employee_id):
    employee = get_object_or_404(Employee, employee_id=employee_id)
    context = {'employee': employee}
    return render(request, 'employee_records/employee.html', context)