Python django如何根据用户状态更改_str________)标签?
我想按用户状态更改选择选项的标签 我的模型是Python django如何根据用户状态更改_str________)标签?,python,django,django-models,django-forms,Python,Django,Django Models,Django Forms,我想按用户状态更改选择选项的标签 我的模型是 class BookCategory(model): label_1 = char label_2 = char def __unicode__(self): #something here? class Book(model): name = char categoey = models.Foreignkey(BookCategory) BookCategory用于createview
class BookCategory(model):
label_1 = char
label_2 = char
def __unicode__(self):
#something here?
class Book(model):
name = char
categoey = models.Foreignkey(BookCategory)
BookCategory用于createview for new book,该页面具有modelform、book.name的textinput和book.catgory的选项
我的目标是如果用户类型==1:
=>显示类别的标签\u 1
如果用户类型==2:
=>显示类别的标签2 我知道“\uuuUnicode\uuuuu”可以显示实例的值,但我想知道如何根据用户的状态更改其字段 有人知道解决办法吗 加: 我的视图和模型非常简单 观点是
class CreateBook(CreateView):
template_name = "template.html"
model = Book
form_class = BookForm
success_url = "success_url"
def form_valid(self, form):
if form.is_valid():
form.save()
形式是
class LessonForm(ModelForm):
class Meta:
model = Book
fields = ('name',
'category',
)
widgets = {
'name': forms.Textarea(attrs={'class': 'text_box'}),
'category': forms.Textinput(attrs={'class': 'select_box'}),
}
子类创建两个自定义模型字段。覆盖label\u from\u instance
以自定义对象在表单中的显示方式
class Type1CategoryField(ModelChoiceField):
def label_from_instance(self, obj):
return obj.label1
class Type2CategoryField(ModelChoiceField):
def label_from_instance(self, obj):
return obj.label1
然后更改表单,使其以user
作为关键字参数,并更改category字段以使用适当的model choice字段
class LessonForm(ModelForm):
class Meta:
model = Book
fields = ('name',
'category',
)
widgets = {
'name': forms.Textarea(attrs={'class': 'text_box'}),
}
def __init__(self, *args, **kwargs):
user = kwargs.pop('user')
super(LessonForm, self).__init__(*args, **kwargs)
if user.user_type == 1:
self.fields['category'] = Type1CategoryField(queryset=Category.objects.all())
elif user.user_type == 2:
self.fields['category'] = Type2CategoryField(queryset=Category.objects.all())
使用forms.Textinput
作为选择字段是没有意义的,因此我从小部件中删除了类别
最后,修改视图,使其在kwargs表单中包含登录用户。使用LoginRequiredMixin
确保只有登录的用户才能访问该视图
from django.contrib.auth.mixins import LoginRequiredMixin
class CreateBook(LoginRequiredMixin, CreateView):
template_name = "template.html"
model = Book
form_class = BookForm
success_url = "success_url"
def get_form_kwargs(self):
kwargs = super(CreateBook, self).get_form_kwargs()
kwargs['user'] = request.user
子类创建两个自定义模型字段。覆盖label\u from\u instance
以自定义对象在表单中的显示方式
class Type1CategoryField(ModelChoiceField):
def label_from_instance(self, obj):
return obj.label1
class Type2CategoryField(ModelChoiceField):
def label_from_instance(self, obj):
return obj.label1
然后更改表单,使其以user
作为关键字参数,并更改category字段以使用适当的model choice字段
class LessonForm(ModelForm):
class Meta:
model = Book
fields = ('name',
'category',
)
widgets = {
'name': forms.Textarea(attrs={'class': 'text_box'}),
}
def __init__(self, *args, **kwargs):
user = kwargs.pop('user')
super(LessonForm, self).__init__(*args, **kwargs)
if user.user_type == 1:
self.fields['category'] = Type1CategoryField(queryset=Category.objects.all())
elif user.user_type == 2:
self.fields['category'] = Type2CategoryField(queryset=Category.objects.all())
使用forms.Textinput
作为选择字段是没有意义的,因此我从小部件中删除了类别
最后,修改视图,使其在kwargs表单中包含登录用户。使用LoginRequiredMixin
确保只有登录的用户才能访问该视图
from django.contrib.auth.mixins import LoginRequiredMixin
class CreateBook(LoginRequiredMixin, CreateView):
template_name = "template.html"
model = Book
form_class = BookForm
success_url = "success_url"
def get_form_kwargs(self):
kwargs = super(CreateBook, self).get_form_kwargs()
kwargs['user'] = request.user
您不能在\uuuuunicode\uuuu
方法中执行此操作,因为您没有访问请求的权限。如果您显示您的视图和表单,您可能可以更改它们以执行您想要的操作。@Alasdair感谢您的建议!我在我的帖子中添加了我的视图和表单。您能告诉我如何将“请求”传递给他们吗?您不能在\uuuuuunicode\uuuuu
方法中执行此操作,因为您没有访问请求的权限。如果您显示您的视图和表单,您可能可以更改它们以执行您想要的操作。@Alasdair感谢您的建议!我在我的帖子中添加了我的视图和表单。你能告诉我如何把“请求”传递给他们吗?