Python 如何避免在满足条件之前推进循环？

我编写了以下程序：

numb= ["First", "Second", "Third"]
players=[]
n = ''
score=[]

for i in numb:
    print("Type the score of the name of the", i, "player:")
    answer = n = str(input(' '))
    players.append(d)

for a in players:
    for b in numb:
        a = int(input("Type the", b, "score of", a))
        if a!=0:
            score.append(a)
        else:

我想避免在numb:中为b推进内部循环

，只要a是0。
例如：如果第一个分数为0，程序将再次打印“键入第一个分数…”。
我想这就是您想要的：

for a in players:
   for b in numb:
       done = False
       while not done:
           a = int(input(f"Type the {b} score of {a}"))
           if a :
               score.append(a)
               done = True

done
开始为False，为True时中断并转到下一个列表元素

离题：我给你的代码添加了一些PEP8，希望你喜欢
 在python>=3.8中，您可以使用新添加的：

for a in players:
    for b in numb:
        while (a := int(input(f"Type the {b} score of {a}")) == 0:
            pass
        score.append(a)