Python：将for循环与列表相关联

我找不到任何解决办法。在我的真实示例中，这将用于将颜色遮罩与对象关联

我认为最好的解释方式是举个例子：

objects = ['pencil','pen','keyboard','table','phone']
colors  = ['red','green','blue']

for n, i in enumerate(objects):
    print n,i #0 pencil

    # print the index of colors

我需要的结果是：

#0 pencil    # 0 red
#1 pen       # 1 green
#2 keyboard  # 2 blue
#3 table     # 0 red
#4 phone     # 1 green

因此，始终会有3种颜色与对象关联，如何在python中的

for

循环中获得此结果？每次n（迭代器）大于颜色列表的长度时，我如何告诉它返回并打印第一个索引，依此类推？

使用

%

：

for n, obj in enumerate(objects):
    print n, obj, colors[n % len(colors)]

或及：

演示：

或

>>> for i, obj, j, color in izip(count(), objects, cycle(range(len(colors))), cycle(colors)):
...     print i, obj, j, color
... 
0 pencil 0 red
1 pen 1 green
2 keyboard 2 blue
3 table 0 red
4 phone 1 green

>>> objects = ['pencil','pen','keyboard','table','phone']
>>> colors  = ['red','green','blue']
>>> for n, obj in enumerate(objects):
...     print n, obj, colors[n % len(colors)]
... 
0 pencil red
1 pen green
2 keyboard blue
3 table red
4 phone green
>>> from itertools import cycle
>>> for n, (obj, color) in enumerate(zip(objects, cycle(colors))):
...     print n, obj, color
... 
0 pencil red
1 pen green
2 keyboard blue
3 table red
4 phone green

>>> from itertools import count, izip, cycle
>>> objects = ['pencil','pen','keyboard','table','phone']
>>> colors  = ['red','green','blue']
>>> for i, obj, color in izip(count(), objects, cycle(colors)):
...     print i, obj, color
... 
0 pencil red
1 pen green
2 keyboard blue
3 table red
4 phone green

>>> for i, obj, j, color in izip(count(), objects, cycle(range(len(colors))), cycle(colors)):
...     print i, obj, j, color
... 
0 pencil 0 red
1 pen 1 green
2 keyboard 2 blue
3 table 0 red
4 phone 1 green