Python OOP-操作对象方法的输出

我试图在一个对象中使用一个方法来操作它，但它总是告诉我数据的类型不匹配

我还在学习，我知道这种问题肯定是每个人在学习过程中迟早都会遇到的，但我找不到一个明确的解释，也找不到像这样的问题。这可能是我需要提高搜索技能的原因

def runSimulation(num_robots, speed, width, height, min_coverage, num_trials, robot_type):
    """
    Runs NUM_TRIALS trials of the simulation and returns the mean number of
    time-steps needed to clean the fraction MIN_COVERAGE of the room.

    The simulation is run with NUM_ROBOTS robots of type ROBOT_TYPE, each with
    speed SPEED, in a room of dimensions WIDTH x HEIGHT.

    num_robots: an int (num_robots > 0)
    speed: a float (speed > 0)
    width: an int (width > 0)
    height: an int (height > 0)
    min_coverage: a float (0 <= min_coverage <= 1.0)
    num_trials: an int (num_trials > 0)
    robot_type: class of robot to be instantiated (e.g. StandardRobot or
                RandomWalkRobot)
    """
    space = RectangularRoom(width, height)
    bots = []
    times = []
    total = 0

    for n in range(num_robots):
        bots.append(StandardRobot(space, speed)) #needs change to robot_type

    for s in range(num_trials):
        test_time = 0
        while space.getNumCleanedTiles/(width*height) < min_coverage:
            for bot in bots:
                bot.updatePositionAndClean()
            test_time += 1
        times.append(test_time)

    for time in times:
        total += time
    return total / len(times)

当我尝试运行它时，它告诉我无法计算space.getNumCleanedTitles/width*height

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我没有包括代码的其余部分，因为它并不重要，而且很清楚什么调用做什么。

@luther得到了答案，我忘了在getNumCleanedTitles后面加上一个“

你似乎在迭代一个emtpy列表。你是对的，我只是忘记了一个s在那里。现在已修复。返回什么类型的space.GetNumCleanedTitles？您忘记调用实例方法。放在GetNumCleanedTitles之后。它是return lenself.cleaned。我现在试着检查一下类型。