Python 如何在二进制加法器中反转输出?
因此,我试图创建一个简单的程序,将两个二进制字符串添加到一起,我几乎完成了,但它创建的输出是反向的,我将如何在代码中实现反向的方法?我还想删除输出开头的“ob”Python 如何在二进制加法器中反转输出?,python,binary,Python,Binary,因此,我试图创建一个简单的程序,将两个二进制字符串添加到一起,我几乎完成了,但它创建的输出是反向的,我将如何在代码中实现反向的方法?我还想删除输出开头的“ob” repeat = True while repeat==True: num1 = input("what number would you like to add ") if num1.isdigit(): a= int(num1) elif not num1.isdigit():
repeat = True
while repeat==True:
num1 = input("what number would you like to add ")
if num1.isdigit():
a= int(num1)
elif not num1.isdigit():
continue
a = int(num1, 2)
num2 = input("what number would you like to add to it ")
if num2.isdigit():
b= int(num2)
elif not num2.isdigit():
continue
b = int(num2, 2)
ans = bin(a+b)[2:]
print("Your addition of numbers, in binary is " + ans)
choice=input("Would you like to start again, y/n")
if choice== "y":
repeat=True
else:
print("Its not like i wanted you here or anything baka")
repeat=False
您可以使用以下方法反转字符串:
ans = ans[::-1]
如果案例:。。。elif not case:…
与相同,如果case:。。。其他:…
除了更多的计算-使用后者isdigit()
也不能保证int()
能正常工作!而是使用try:int(…)来捕获异常,ValueError除外:…
。