Python'；s类继承_Python_Class_Inheritance

Python'；s类继承

python class inheritance

Python'；s类继承,python,class,inheritance,Python,Class,Inheritance,实例化类时，不需要传入base\u class。这是在定义上完成的\uuuu init\uuuu只接受一个参数，即self，并且是自动的。你只需要打个电话 # Defining a Base class to be shared among many other classes later: class Base(dict): """Base is the base class from which all the class will derrive. """ nam

实例化类时，不需要传入

base\u class

。这是在定义上完成的<代码>\uuuu init\uuuu只接受一个参数，即

self

，并且是自动的。你只需要打个电话

# Defining a Base class to be shared among many other classes later:

class Base(dict):
    """Base is the base class from which all the class will derrive.
    """
    name = 'name'    
    def __init__( self):
        """Initialise Base Class
        """
        dict.__init__(self)
        self[Base.name] = ""

# I create an instance of the Base class:

my_base_instance = Base()

# Since a Base class inherited from a build in 'dict' the instance of the class is a dictionary. I can print it out with:

print my_base_instance   Results to: {'name': ''}


# Now I am defining a Project class which should inherit from an instance of Base class:

class Project(object):
    def __init__(self):
        print "OK"
        self['id'] = ''

# Trying to create an instance of Project class and getting the error:

project_class = Project(base_class)

TypeError: __init__() takes exactly 1 argument (2 given)

实例化类时，不需要传入

base\u class

。这是在定义上完成的<代码>\uuuu init\uuuu只接受一个参数，即

self

，并且是自动的。你只需要打个电话

# Defining a Base class to be shared among many other classes later:

class Base(dict):
    """Base is the base class from which all the class will derrive.
    """
    name = 'name'    
    def __init__( self):
        """Initialise Base Class
        """
        dict.__init__(self)
        self[Base.name] = ""

# I create an instance of the Base class:

my_base_instance = Base()

# Since a Base class inherited from a build in 'dict' the instance of the class is a dictionary. I can print it out with:

print my_base_instance   Results to: {'name': ''}


# Now I am defining a Project class which should inherit from an instance of Base class:

class Project(object):
    def __init__(self):
        print "OK"
        self['id'] = ''

# Trying to create an instance of Project class and getting the error:

project_class = Project(base_class)

TypeError: __init__() takes exactly 1 argument (2 given)

实例化类时，不需要传入

base\u class

。这是在定义上完成的<代码>\uuuu init\uuuu只接受一个参数，即

self

，并且是自动的。你只需要打个电话

# Defining a Base class to be shared among many other classes later:

class Base(dict):
    """Base is the base class from which all the class will derrive.
    """
    name = 'name'    
    def __init__( self):
        """Initialise Base Class
        """
        dict.__init__(self)
        self[Base.name] = ""

# I create an instance of the Base class:

my_base_instance = Base()

# Since a Base class inherited from a build in 'dict' the instance of the class is a dictionary. I can print it out with:

print my_base_instance   Results to: {'name': ''}


# Now I am defining a Project class which should inherit from an instance of Base class:

class Project(object):
    def __init__(self):
        print "OK"
        self['id'] = ''

# Trying to create an instance of Project class and getting the error:

project_class = Project(base_class)

TypeError: __init__() takes exactly 1 argument (2 given)

实例化类时，不需要传入

base\u class

。这是在定义上完成的<代码>\uuuu init\uuuu只接受一个参数，即

self

，并且是自动的。你只需要打个电话

# Defining a Base class to be shared among many other classes later:

class Base(dict):
    """Base is the base class from which all the class will derrive.
    """
    name = 'name'    
    def __init__( self):
        """Initialise Base Class
        """
        dict.__init__(self)
        self[Base.name] = ""

# I create an instance of the Base class:

my_base_instance = Base()

# Since a Base class inherited from a build in 'dict' the instance of the class is a dictionary. I can print it out with:

print my_base_instance   Results to: {'name': ''}


# Now I am defining a Project class which should inherit from an instance of Base class:

class Project(object):
    def __init__(self):
        print "OK"
        self['id'] = ''

# Trying to create an instance of Project class and getting the error:

project_class = Project(base_class)

TypeError: __init__() takes exactly 1 argument (2 given)

对于要从基继承的项目，您不应该从对象中将其子类化，而应该从基继承，即

类项目（基）

。您将得到

TypeError:init（）在实例化项目类时正好接受1个参数（给定2个）

错误，因为构造函数只接受1个参数（

self

），并且您也传递了

base\u class

）<代码>'self'由python隐式传递。

对于要从基继承的项目，您不应该从对象中将其子类化，而应该从基继承，即

将项目（基）

分类。您将得到

TypeError:init（）在实例化项目类时正好接受1个参数（给定2个）

错误，因为构造函数只接受1个参数（

self

），并且您也传递了

base\u class

）<代码>'self'由python隐式传递。

对于要从基继承的项目，您不应该从对象中将其子类化，而应该从基继承，即

将项目（基）

分类。您将得到

TypeError:init（）在实例化项目类时正好接受1个参数（给定2个）

错误，因为构造函数只接受1个参数（

self

），并且您也传递了

base\u class

）<代码>'self'由python隐式传递。

对于要从基继承的项目，您不应该从对象中将其子类化，而应该从基继承，即

将项目（基）

分类。您将得到

TypeError:init（）在实例化项目类时正好接受1个参数（给定2个）

错误，因为构造函数只接受1个参数（

self

），并且您也传递了

base\u class

）<代码>'self'由python隐式传递。

代码中有两个错误：

1）类继承

project_class = Project()

2）实例定义（您的

\uuuuu init\uuuu

不需要任何显式参数，当然也不需要祖先类）

代码中有两个错误：

1）类继承

project_class = Project()

2）实例定义（您的

\uuuuu init\uuuu

不需要任何显式参数，当然也不需要祖先类）

代码中有两个错误：

1）类继承

project_class = Project()

2）实例定义（您的

\uuuuu init\uuuu

不需要任何显式参数，当然也不需要祖先类）

代码中有两个错误：

1）类继承

project_class = Project()

2）实例定义（您的

\uuuuu init\uuuu

不需要任何显式参数，当然也不需要祖先类）

定义类时必须声明继承性（

class-Project（Base）

而不是实例化它。定义类时必须声明继承性（

class-Project（Base）

而不是实例化它。定义类时必须声明继承性（

class-Project（Base）

而不是在实例化它时。定义类时必须声明继承性（

类项目（基）

而不是在实例化它时。