Python for-in-loop如何处理多个序列

我遇到了以下for循环代码，但不太清楚它是如何运行的：

for sentence in snippet, phrase:
    result = sentence[:]

它是通过“片段”然后是“短语”进行迭代的吗

编辑：

PHRASES = {
"class %%%(%%%):":
  "Make a class named %%% that is-a %%%.",
"class %%%(object):\n\tdef __init__(self, ***)" :
  "class %%% has-a __init__ that takes self and *** parameters.",
"class %%%(object):\n\tdef ***(self, @@@)":
  "class %%% has-a function named *** that takes self and @@@ parameters.",
"*** = %%%()":
  "Set *** to an instance of class %%%.",
"***.***(@@@)":
  "From *** get the *** function, and call it with parameters self, @@@.",
"***.*** = '***'":
  "From *** get the *** attribute and set it to '***'."
}

##############
#'snippet' is a key in the dict shown above, and 'phrase' is its corresponding value
def convert(snippet, phrase):
class_names = [w.capitalize() for w in
               random.sample(WORDS, snippet.count("%%%"))]
other_names = random.sample(WORDS, snippet.count("***"))
results = []
param_names = []

for i in range(0, snippet.count("@@@")):
    param_count = random.randint(1,3)
    param_names.append(', '.join(random.sample(WORDS, param_count)))

########
#Here is the code in question
########
for sentence in snippet, phrase:
    result = sentence[:]

    # fake class names
    for word in class_names:
        result = result.replace("%%%", word, 1)

    # fake other names
    for word in other_names:
        result = result.replace("***", word, 1)

    # fake parameter lists
    for word in param_names:
        result = result.replace("@@@", word, 1)

    results.append(result)

return results

---

否。

snippet，phrase

仅定义这两个元素的元组。迭代在该元组之上；ie语句首先是

片段的值，然后是
短语的值。它不会遍历这些值的内容。
请包含一个更完整的示例。对于（代码段、短语）中的句子，它与
相同。
<代码>句子
将在第一次迭代中设置为
片段
，在第二次迭代中设置为
短语
。你可以在大约5秒钟内测试出来。你说“句子是…的第一个值”，然后你说“它不会遍历…的内容”。内容和价值有什么区别？