Python 字典理解值为列表

嗨，我有以下字典

players = {
    "Brazil": [
        (12, "Júlio César", "Goalkeeper", []),
        (4, "David Luiz", "Defender", []),
        (6, "Marcelo", "Defender", []),
        (13, "Dante", "Defender", []),
        (23, "Maicon", "Defender", []),
        (5, "Fernandinho", "Midfielder", []),
        (7, "Hulk", "Midfielder", []),
        (8, "Paulinho", "Midfielder", []),
        (11, "Oscar", "Midfielder", [90]),
        (16, "Ramires", "Midfielder", []),
        (17, "Luiz Gustavo", "Midfielder", []),
        (19, "Willian", "Midfielder", []),
        (9, "Fred", "Striker", []),
    ],
    "Germany": [
        (1, "Manuel Neuer", "Goalkeeper", []),
        (4, "Benedikt Höwedes", "Defender", []),
        (5, "Mats Hummels", "Defender", []),
        (16, "Philipp Lahm", "Defender", []),
        (17, "Per Mertesacker", "Defender", []),
        (20, "Jérôme Boateng", "Defender", []),
        (6, "Sami Khedira", "Midfielder", [29]),
        (7, "Bastian Schweinsteiger", "Midfielder", []),
        (8, "Mesut Özil", "Midfielder", []),
        (13, "Thomas Müller", "Midfielder", [11]),
        (14, "Julian Draxler", "Midfielder", []),
        (18, "Toni Kroos", "Midfielder", [24, 26]),
        (9, "André Schürrle", "Striker", [69, 79]),
        (11, "Miroslav Klose", "Striker", [23]),
    ],
}

是否可以创建一个包含所有巴西球员的字典，名字作为键，第一个数字作为单行字典中的值？ 输出应为：

{'Júlio César': 12, 'David Luiz': 4, 'Marcelo': 6, 'Dante': 13, 'Maicon': 23, 'Fernandinho': 5, 'Hulk': 7, 'Paulinho': 8, 'Oscar': 11, 'Ramires': 16, 'Luiz Gustavo': 17, 'Willian': 19, 'Fred': 9}

当然有可能

brazil={player:number for（number，player，u，u）在players[“brazil”]}
#{'Júlio César'：12，'David Luiz'：4，'Marcelo'：6，'Dante'：13，'Maicon'：23，'Fernandino'：5，'Hulk'：7，'Paulinho'：8，'Oscar'：11，'Ramires'：16，'Luiz Gustavo'：17，'Willian'：19，'Fred'：9}

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这是通过从源数据展开元组列表中的每个元组来实现的。您要使用的键和值是命名的，而下划线是表示您不想使用元组的这些部分的常规方式

您能证明自己在解决这个问题上做了哪些努力吗？例如，在不理解的情况下解决问题时，“告诉我如何解决这个编码问题”是非常重要的。你需要先做一个测试，然后问一个关于你的实现的具体问题。我是用两行程序来做的，但我想用一行程序来解决它。所以我在这里问：谢谢：）这会很有帮助的。