Python _curses.error:addstr()返回错误
使用Python,我试图编写一个脚本,每当您按下空格键时,它会将所有键入的字符转换为“a”。例如,我先键入“python”,然后键入空格,然后将“python”转换为“aaaaa” 上面的代码在第1行可以正常工作,但是,在第2行中,每当我按下空格键时,第22行就会出现一个错误:“_curses.error:addstr()returned ERR” 编辑: 当我将screen.addstr(dim[0],dim-count-1,h)更改为screen.addstr(dim[0],dim-count,h)时,错误被消除,但输出不是我想要的。我已附上输出供您参考 我认为if语句也是为回车符和\或换行符执行的,所以我认为由于第一行,您的计数比您预期的多1 addstr()返回的错误异常是由于以下原因导致光标被移出屏幕(超出范围):Python _curses.error:addstr()返回错误,python,python-2.7,python-3.x,curses,python-curses,Python,Python 2.7,Python 3.x,Curses,Python Curses,使用Python,我试图编写一个脚本,每当您按下空格键时,它会将所有键入的字符转换为“a”。例如,我先键入“python”,然后键入空格,然后将“python”转换为“aaaaa” 上面的代码在第1行可以正常工作,但是,在第2行中,每当我按下空格键时,第22行就会出现一个错误:“_curses.error:addstr()returned ERR” 编辑: 当我将screen.addstr(dim[0],dim-count-1,h)更改为screen.addstr(dim[0],dim-coun
由于第一行末尾的回车(\r),您的计数为+1。第一个if应检查此项,而不是增加计数。尝试添加这些检查
s=诅咒,钥匙,快进去=10和s=13
查看第一个if,看看是否有帮助<代码>s=10将检查新行字符(\n)(在这种情况下可能不需要,但我是强迫症患者)<代码>s=13将检查回车符(\r)。有多个地方可以改进给定的示例。以下是修订版:
import curses
import time
# Main Function
def main():
screen=curses.initscr()
curses.cbreak()
screen.keypad(1)
curses.echo()
screen.scrollok(1)
str_txt=''
count = 0
while True:
dim = screen.getyx()
s=screen.getch()
if s != ord(' ') and s != ord('\x1b') and s != curses.KEY_BACKSPACE and s != curses.KEY_ENTER and s != 10 and s != 13:
str_txt += chr(int(s))
count+=1
if s == ord(' '):
if count > 0:
h = 'a'*len(str_txt)+' '
screen.addstr(dim[0],dim[1]-count, h)
count=0
str_txt=''
if s == curses.KEY_ENTER or s==10 or s==13:
if count > 0:
h = 'a'*len(str_txt)
screen.addstr(dim[0],dim[1]-count, h)
count=0
str_txt=''
screen.move(dim[0]+1,0)
count=0
str_txt=''
#if s == curses.KEY_BACKSPACE:
# dim = screen.getyx()
# screen.move(dim[0],dim[1])
# screen.refresh()
if s == ord('\x1b'):
curses.endwin()
break
if __name__ == "__main__":
main()
例如:
- 不需要screen.refresh调用,因为screen.getch会这样做
- 未进行检查以确保计数为非零
- 按enter键(或return键)与空格键的行为不同
- 回车后的移动移动了两行而不是一行
- 屏幕不会在末尾滚动(本例中为部分修复)
if s != ord(' ') and s != ord('\x1b') and s != curses.KEY_BACKSPACE:
str_txt += chr(int(s))
count+=1
screen.addstr(dim[0],dim[1]-count-1, h)
import curses
import time
# Main Function
def main():
screen=curses.initscr()
curses.cbreak()
screen.keypad(1)
curses.echo()
screen.scrollok(1)
str_txt=''
count = 0
while True:
dim = screen.getyx()
s=screen.getch()
if s != ord(' ') and s != ord('\x1b') and s != curses.KEY_BACKSPACE and s != curses.KEY_ENTER and s != 10 and s != 13:
str_txt += chr(int(s))
count+=1
if s == ord(' '):
if count > 0:
h = 'a'*len(str_txt)+' '
screen.addstr(dim[0],dim[1]-count, h)
count=0
str_txt=''
if s == curses.KEY_ENTER or s==10 or s==13:
if count > 0:
h = 'a'*len(str_txt)
screen.addstr(dim[0],dim[1]-count, h)
count=0
str_txt=''
screen.move(dim[0]+1,0)
count=0
str_txt=''
#if s == curses.KEY_BACKSPACE:
# dim = screen.getyx()
# screen.move(dim[0],dim[1])
# screen.refresh()
if s == ord('\x1b'):
curses.endwin()
break
if __name__ == "__main__":
main()