Python Pymysql插入外键错误
我的餐桌上的天气Python Pymysql插入外键错误,python,mysql,python-3.x,Python,Mysql,Python 3.x,我的餐桌上的天气 create table weather ( time timestamp default current_timestamp on update current_timestamp, id smallint, tpr float(3,1), wet float(3,1), uv tinyint(2), foreign key (id)
create table weather (
time timestamp default current_timestamp on update current_timestamp,
id smallint,
tpr float(3,1),
wet float(3,1),
uv tinyint(2),
foreign key (id) references database.station(pk));
台站
CREATE TABLE station(
pk SMALLINT(5) NOT NULL AUTO_INCREMENT,
name VARCHAR(5),
lng DOUBLE(10,6),
lat DOUBLE(10,6),
PRIMARY KEY(pk));
当我使用pymysql将id插入天气时
我做了以下两个功能:
conn = pymysql.connect()#ignore the details
def get_id_from_station():
sql = """SELECT pk FROM station """
conn.cursor().execute(sql)
id = conn.cursor().fetchone()[0]
weather_saved(id)
def weather_saved(id):
#get the time,tpr,wet,uv value
sql = """INSERT INTO weather (time,id,tpr,wet,uv) VALUES (%s,%s,%s,%s,%s)"""
db.execute(sql, (time, id,tpr, wet, uv))
但是天气表没有更新
怎么了 以下是更新天气表的代码。我使用了Python2.7,但应该是相同的。我认为您的问题可能是您没有提交插入
import pymysql
conn = pymysql.connect(...)
def get_id_from_station():
sql = """SELECT pk FROM station """
cursor = conn.cursor()
cursor.execute(sql)
row = cursor.fetchone()
weather_saved(row)
import time
import datetime
def weather_saved(id):
#get the time,tpr,wet,uv value
sql = """INSERT INTO weather (time,id,tpr,wet,uv) VALUES (%s,%s,%s,%s,%s)"""
cursor = conn.cursor()
ts = time.time()
timestamp = datetime.datetime.fromtimestamp(ts).strftime('%Y-%m-%d %H:%M:%S')
cursor.execute(sql, (timestamp, id,7, 7, 7))
conn.commit()
get_id_from_station()