Fatal编程技术网
  • python/
  • Python 发送电子邮件时抄送列表不工作

Python 发送电子邮件时抄送列表不工作

python

Python 发送电子邮件时抄送列表不工作,python,Python,我有以下发送电子邮件的代码，问题是CC选项似乎不起作用，这意味着CC组中的人没有收到电子邮件，作为一项测试，我将组改为以列出它的工作原理，那么有没有关于如何解决此问题的指导 from email.mime.text import MIMEText from email.MIMEMultipart import MIMEMultipart import smtplib def sendEmail2(type,data): email ='username@company.com'

我有以下发送电子邮件的代码，问题是
CC
选项似乎不起作用，这意味着
CC
组中的人没有收到电子邮件，作为一项测试，我将组改为
以
列出它的工作原理，那么有没有关于如何解决此问题的指导


from email.mime.text import MIMEText
from email.MIMEMultipart import MIMEMultipart
import smtplib

def sendEmail2(type,data):
    email ='username@company.com'
    body = '''%s''' % (data)
    msg = MIMEMultipart()
    sender = 'techci@company.com'
    receivers = []
    cc = ['team-tech-integrators@group.company.com']
    REPLY_TO_ADDRESS = 'team-tech-integrators@group.company.com'
    if type =='OPERATIONfailure':
        b = '\U0001F6A8'
        receivers.append(email)
        msg['Subject'] = '%s AUTO OPERATION FAILED FOR GERRIT  :PLEASE TAKE IMMEDIATE ACTION!!!'%(b.decode('unicode-escape'))
    elif type == 'git_push_success':
        b = '\U0001F600'
        receivers = ['team-tech-integrators@group.company.com']
        msg['Subject'] = '%s AUTO OPERATION SUCCESS FOR !!!'%(b.decode('unicode-escape'))
    msg['From'] = sender
    msg['To'] = ', '.join(receivers)
    msg['Cc'] = ','.join(cc)
    msg["Content-Type"] = "text/html"
    try:
        mail = smtplib.SMTP('relay.company.com', 25)
        msg.attach(MIMEText(body, 'html'))
        msg.add_header('reply-to', REPLY_TO_ADDRESS)
        mail.sendmail(sender, receivers, msg.as_string())
    except Exception as e:
        print e
        print "Problem sending email"

def main():
    data = "test"
    sendEmail2("OPERATIONfailure",data)
if __name__ == "__main__":
    main()



您是否打印了
msg.as_string（）
以查看正在生成的实际MIME内容？您是否尝试在
'上加入
Cc
，“
而不是
”，“
（添加尾随空格，就像您的
到
字段的方式一样）？