Python Tkinter问题与if块中的标签

我对tkinter中if语句中的标签有问题，与try/except块类似

我正在尝试创建一个基于csv数据的口袋妖怪战斗模拟器

这是从csv中提取数据，但当有人输入一个不在base中的名称时，豁免机制不起作用

     else:
            my_label = Label(root, text="Oops! I don't think we got such Pokemon archive.", font=("Comic Sans", 20))
            my_label.grid(row=1, column=1)

我想让程序显示带有文本的附加标签，但它不起作用。而是冻结了一个程序，所以我无法发现错误，也无法找出原因。有人能告诉我怎么解决这个问题吗

   from tkinter import *


def create_pokemon_b():
    import pandas as pd
    df_pokemons = pd.read_csv('/home/js/PycharmProjects/untitled/main_Pokemon.csv')
    while True:
        name = str(entry_pokename_b.get()).capitalize()
        if name in list(df_pokemons['pokename']):
            while True:
                level = entry_pokelevel_b.get()
                try:
                    level = int(level)
                    speed = int(df_pokemons[(df_pokemons['pokename'] == name) & (df_pokemons['pokelevel'] == level)][
                                    'speed'].mean())
                    hp = int(df_pokemons[(df_pokemons['pokename'] == name) & (df_pokemons['pokelevel'] == level)][
                                 'hp'].mean())
                    att = int(df_pokemons[(df_pokemons['pokename'] == name) & (df_pokemons['pokelevel'] == level)][
                                  'attack'].mean())
                    defense = int(df_pokemons[(df_pokemons['pokename'] == name) & (df_pokemons['pokelevel'] == level)][
                                      'defense'].mean())
                    type1 = str(df_pokemons[(df_pokemons['pokename'] == name) & (df_pokemons['pokelevel'] == level)][
                                    'type1'].unique()[0])
                    stats = Label(root,
                                  text='{} on level {}: \nType = {} \nHP = {} \nDefense = {} \nSpeed = {}\nAttack = {}\n'.format(
                                      name, level, type1, hp, defense, speed, att), font=("Comic Sans", 15))
                    stats.grid(row=7, column=1, columnspan=6, rowspan=6)
                    global poke_b
                    poke_b = tuple(type1, name, level, speed, hp, defense, att)

                except ValueError:
                    error = Label(root, text="Oops! I don't think we got such Pokemon archive.",
                                  font=("Comic Sans", 20))
                    error.grid(row=7, column=1)
        else:
            my_label = Label(root, text="Oops! I don't think we got such Pokemon archive.", font=("Comic Sans", 20))
            my_label.grid(row=1, column=1)


root = Tk()

my_label = Label(root)
my_label.grid(row=1, column=1)
#entry fields where name and level of pokemon B are entered

label_pokename = Label(root, text='Enter name of Pokemon A.',font=("Comic Sans", 15))
label_pokelevel = Label(root, text='What is it\'s level?',font=("Comic Sans", 15))

entry_pokename = Entry(root, width=40, font=("Comic Sans", 15))
entry_pokelevel = Entry(root, width=40, font=("Comic Sans", 15))

label_pokename.grid(row=0)
entry_pokename.grid(row=1)
label_pokelevel.grid(row=2)
entry_pokelevel.grid(row=3)

#statistics field

stats = Label(root)
stats.grid(row=1,column=1, columnspan=6, rowspan=6)

#button starting function used to pull pokemon data from the csv

button_a = Button(root, text='Search',font=("Comic Sans", 15),command=create_pokemon_a)
button_a.grid(row=4)

root.mainloop()

---

迈克-SMT，谢谢你的回答。事实上，当我删除while语句时，代码开始工作

def create_pokemon_b():
    import pandas as pd
    df_pokemons = pd.read_csv('/home/js/PycharmProjects/untitled/main_Pokemon.csv')
        name = str(entry_pokename_b.get()).capitalize()
        if name in list(df_pokemons['pokename']):
                level = entry_pokelevel_b.get()
                try:
                    level = int(level)
                    speed = int(df_pokemons[(df_pokemons['pokename'] == name) & (df_pokemons['pokelevel'] == level)][
                                    'speed'].mean())
                    hp = int(df_pokemons[(df_pokemons['pokename'] == name) & (df_pokemons['pokelevel'] == level)][
                                 'hp'].mean())
                    att = int(df_pokemons[(df_pokemons['pokename'] == name) & (df_pokemons['pokelevel'] == level)][
                                  'attack'].mean())
                    defense = int(df_pokemons[(df_pokemons['pokename'] == name) & (df_pokemons['pokelevel'] == level)][
                                      'defense'].mean())
                    type1 = str(df_pokemons[(df_pokemons['pokename'] == name) & (df_pokemons['pokelevel'] == level)][
                                    'type1'].unique()[0])
                    stats = Label(root,
                                  text='{} on level {}: \nType = {} \nHP = {} \nDefense = {} \nSpeed = {}\nAttack = {}\n'.format(
                                      name, level, type1, hp, defense, speed, att), font=("Comic Sans", 15))
                    stats.grid(row=7, column=1, columnspan=6, rowspan=6)
                    global poke_b
                    poke_b = tuple(type1, name, level, speed, hp, defense, att)

                except ValueError:
                    error = Label(root, text="Oops! I don't think we got such Pokemon archive.",
                                  font=("Comic Sans", 20))
                    error.grid(row=7, column=1)
        else:
            my_label = Label(root, text="Oops! I don't think we got such Pokemon archive.", font=("Comic Sans", 20))
            my_label.grid(row=1, column=1)

---

这里有很多代码，您的问题不够具体。你犯了什么错误？什么线路导致了问题？请阅读和。感谢您的评论，我已对我的问题进行了更具体的编辑，以便更好地理解我的问题。我可以告诉您

，而True

语句可能是导致代码冻结的原因。不要在tkinter的同一线程中使用

while

语句或

sleep（）

，因为它们会阻塞主循环并冻结程序。也就是说，将所有导入都移动到代码的顶部。不要将导入放在函数中。每次有人按下按钮，你就会无缘无故地一次又一次地导入。它只需要在代码开始时发生一次。同时将您的

global

放在函数的开头。“它只是更容易阅读和处理。我同意每件事，”迈克说。此外，在这种情况下，您的

while True:

似乎是一个无限循环（即使发生

ValueError

），这在非tkinter应用程序中也是错误的。