按索引顺序为特定ID组装字符串。python

所以我有一个子列表

子列表的第一个值是ID，第二个值是索引

最终，我将尝试按照索引的顺序为每个ID组合字符串。

raw_IDs = ['TCONS_0040771;1','TCONS_0040771;2','TCONS_0040771;3','TCONS_00040772;1','TCONS_00040772;2','TCONS_00040773;1','TCONS_00040773;2','TCONS_00040773;3','TCONS_00040773;4']

IDs = [['TCONS_0040771',1],['TCONS_0040771',2],['TCONS_0040771',3],['TCONS_00040772',1],['TCONS_00040772',2],['TCONS_00040773',1],['TCONS_00040773',2],['TCONS_00040773',3],['TCONS_00040773',4]]

我有每个值的序列字典，所以

sequences = []

for k in raw_IDs:
    sequences.append(D_ID_seq[k])
print sequences

sequences = ['AAA','AAB','AAAB','AAAA','BAA','BBA','BBB','CCC','DDD']  

我正在尝试根据ID、TCONS\u xxx值来组装序列

desired_output = ['AAAAABAAAB','AAAABAA','BBABBBCCCDDD']

示例：ID中的前3个元素都具有相同的ID“TCONS\u 0040771”。然而，它们的指数从1到3不等。这对索引1-2的“TCONS\u 0040772”和索引1-4的“TCONS\u 0040773”重复

所需输出是根据相应ID从附加到名为“序列”列表的字典值中收集的所有字符串的组合

注*** 我曾想过创建一个while循环，但有时我尝试它们时，它们会变得非常混乱，最终会运行无限长的时间

非常感谢使用以下数据提供的任何帮助

：

# This assumes raw_IDs[] and sequences[] have been defined
IDs = [id.split(';') for id in raw_IDs]

prev_id = None
desired_output = []
for id in IDs.keys()
    if id != prev_id:
        if prev_id:
            desired_output.append(output)
        output = ''
    output += sequences.pop(0)
if output:
    desired_output.append(output)

IDs = [['TCONS_0040771', 1], ['TCONS_0040771', 2], ['TCONS_0040771', 3],
       ['TCONS_00040772', 1], ['TCONS_00040772', 2], ['TCONS_00040773', 1],
       ['TCONS_00040773', 2], ['TCONS_00040773', 3], ['TCONS_00040773', 4]]
sequences = ['AAA','AAB','AAAB','AAAA','BAA','BBA','BBB','CCC','DDD']

此代码：

last_id = IDs[0][0]
res = [sequences[0]]
for index, (id_, _) in enumerate(IDs[1:], 1):
    if id_ == last_id:
        res[-1] += sequences[index]
    else:
        res.append(sequences[index])
    last_id = id_

为

res

提供此选项：

['AAAAABAAAB', 'AAAABAA', 'BBABBBCCCDDD']