Python 字符串列表上的字符串操作

我有以下字符串列表：

['2018-10-02 00:00:13,824 INFO  [Pop3SSLServer-1631] [ip=192.168.15.15;oip=190.73.158.8;] security - cmd=Auth; account=kshovelbottomhz_30@ucab.edu.ve; protocol=pop3;\n', '2018-10-02 00:00:15,941 INFO  [Pop3SSLServer-1632] [ip=192.168.15.15;oip=209.85.167.142;] security - cmd=Auth; account=ditzakmz@ucab.edu.ve; protocol=pop3;\n', '2018-10-02 00:00:26,352 INFO  [Pop3SSLServer-1629] [ip=192.168.15.15;oip=209.85.160.166;] security - cmd=Auth; account=bfermerox_21@ucab.edu.ve; protocol=pop3;\n', '2018-10-02 00:00:33,751 INFO  [Pop3SSLServer-1630] [ip=192.168.15.15;oip=209.85.208.131;] security - cmd=Auth; account=bhansenim@ucab.edu.ve; protocol=pop3;\n', '2018-10-02 00:00:57,661 INFO  [Pop3SSLServer-1631] [ip=192.168.15.15;oip=209.85.222.159;] security - cmd=Auth; account=afellibrand67@ucab.edu.ve; protocol=pop3;\n', '2018-10-02 00:01:05,645 INFO  [Pop3SSLServer-1632] [ip=192.168.15.15;oip=209.85.161.37;] security - cmd=Auth; account=sdenys9q@ucab.edu.ve; protocol=pop3;\n', '2018-10-02 00:01:18,683 INFO  [Pop3SSLServer-1633] [ip=192.168.15.15;oip=209.85.167.24;] security - cmd=Auth; account=lpidonqc@ucab.edu.ve; protocol=pop3;']

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我已经用Python获得了这个列表。我的问题是如何获得每个IP的特定信息。例如192.168.15.15或列表中留下的每个IP，例如90.73.158.8、209.85.167.142等。出现的每个协议，例如pop3。感谢您

以积极的前瞻性使用re完成此任务：

import re
In [1]: a = ['2018-10-02 00:00:13,824 INFO [Pop3SSLServer-1631] [ip=192.168.15.15;oip=190.
   ...: 73.158.8;] security - cmd=Auth; account=kshovelbottomhz_30@ucab.edu.ve; protocol=p
   ...: op3;\n', '2018-10-02 00:00:15,941 INFO [Pop3SSLServer-1632] [ip=192.168.15.15;oip=
   ...: 209.85.167.142;] security - cmd=Auth; account=ditzakmz@ucab.edu.ve; protocol=pop3;
   ...: \n', '2018-10-02 00:00:26,352 INFO [Pop3SSLServer-1629] [ip=192.168.15.15;oip=209.
   ...: 85.160.166;] security - cmd=Auth; account=bfermerox_21@ucab.edu.ve; protocol=pop3;
   ...: \n', '2018-10-02 00:00:33,751 INFO [Pop3SSLServer-1630] [ip=192.168.15.15;oip=209.
   ...: 85.208.131;] security - cmd=Auth; account=bhansenim@ucab.edu.ve; protocol=pop3;\n'
   ...: , '2018-10-02 00:00:57,661 INFO [Pop3SSLServer-1631] [ip=192.168.15.15;oip=209.85.
   ...: 222.159;] security - cmd=Auth; account=afellibrand67@ucab.edu.ve; protocol=pop3;\n
   ...: ', '2018-10-02 00:01:05,645 INFO [Pop3SSLServer-1632] [ip=192.168.15.15;oip=209.85
   ...: .161.37;] security - cmd=Auth; account=sdenys9q@ucab.edu.ve; protocol=pop3;\n', '2
   ...: 018-10-02 00:01:18,683 INFO [Pop3SSLServer-1633] [ip=192.168.15.15;oip=209.85.167.
   ...: 24;] security - cmd=Auth; account=lpidonqc@ucab.edu.ve; protocol=pop3;']

In [2]: for i in a:
   ...:     print(re.findall(r'(?<=ip=)([\d\.]+)', i))
   ...:

['192.168.15.15', '190.73.158.8']
['192.168.15.15', '209.85.167.142']
['192.168.15.15', '209.85.160.166']
['192.168.15.15', '209.85.208.131']
['192.168.15.15', '209.85.222.159']
['192.168.15.15', '209.85.161.37']
['192.168.15.15', '209.85.167.24']

重新导入
在[1]中：a=['2018-10-02 00:00:13824信息[POP3SSLSLServer-1631][ip=192.168.15.15；oip=190。
…：73.158.8；]security-cmd=Auth；account=kshovelbottomhz_30@ucab.edu.ve；协议=p
…：op3；\n'，2018-10-02 00:00:15941信息[POP3SSLSLServer-1632][ip=192.168.15.15；oip=
…：209.85.167.142；]security-cmd=Auth；account=ditzakmz@ucab.edu.ve；协议=pop3；
…：\n'，2018-10-02 00:00:26352信息[POP3SSLSLServer-1629][ip=192.168.15.15；oip=209。
…：85.160.166；]security-cmd=Auth；account=bferrox_21@ucab.edu.ve；协议=pop3；
…：\n'，2018-10-02 00:00:33751信息[POP3SSLSLServer-1630][ip=192.168.15.15；oip=209。
…：85.208.131；]security-cmd=Auth；account=bhansenim@ucab.edu.ve；协议=pop3；\n'
…：，'2018-10-02 00:00:57661信息[POP3SSLSLServer-1631][ip=192.168.15.15；oip=209.85。
…：222.159；]security-cmd=Auth；帐户=afellibrand67@ucab.edu.ve；协议=pop3；\n
…：'，'2018-10-02 00:01:05645信息[POP3SSLSLServer-1632][ip=192.168.15.15；oip=209.85
…：.161.37；]security-cmd=Auth；帐户=sdenys9q@ucab.edu.ve；协议=pop3；\n'，2
…：018-10-02 00:01:18683信息[POP3SSLSLServer-1633][ip=192.168.15.15；oip=209.85.167。
…：24；]security-cmd=Auth；帐户=lpidonqc@ucab.edu.ve；协议=pop3；']
在[2]中：对于a中的i：
你试过什么？你有什么特别的困难？到目前为止你试过什么？