Python 将两个字典中的元素放入列表中

我正在读一个文件，统计整个fasta文件中的氨基酸数量。到目前为止，一切进展顺利。 然后我需要计算百分比，并输出最高的五个，带有氨基酸缩写、计数计数和百分比。我有所有的元素，但在那之后我遇到了麻烦。我有两个字典，两个字典中的键相同，但值不同（tally和percentage）。我曾试图将这两本词典合并成一个单子，但我很难做到

counts = {}

#open file, read line at a time
for line in open('e_coli_k12_dh10b.faa', 'r'):
line = line.rstrip()    
#ignore header line
if line.startswith('>'):continue
for aa in line:
    #if key in dict, add 1
    if aa in counts:
        counts[aa] += 1           
    #else, (if empty) for aa, set to 1
    else:
        counts.update({aa:1})

#get sum of all dictionary values
total = sum(counts[item] for item in counts)

#iterate over values, add to dictionary divided by total * 100
#new dict for percentages
centages = {}

for aa, tally in counts.items():
    #maths for percentages
    percent = (1. * tally / total * 100)  

#within for loop, add aa and percent to centages    
centages.update({aa: percent})


print(counts.keys())
print(counts.values())
print(centages.keys())
print(centages.values())

计数字典 世纪词典 这就是我遇到的问题-我有列表中的第一个dictionary元素，但需要将centages.values添加到适当的位置。我一直在尝试：

    #for loop to set aa to list as keys - [counts.keys, 
counts.values, centages.values]
L = []
for aa, tally in counts.items():
    L.append([aa, tally])

#add centages.values to list L at aa
for i in range(len(counts)):
    for aa, percent in centages.items():
        if(L[i] == centages.keys):
            L[i].append(centages.values)

print(L)    #just aa, tally so far

电流输出：

[['A', 123885], ['C', 14983], ['E', 74992], ['D', 66618], ['G', 95475], ['F', 50554], ['I', 77836], ['H', 29255], ['K', 57151], ['M', 36759], ['L', 139002], ['N', 50492], ['Q', 57732], ['P', 57595], ['S', 74803], ['R', 71819], ['U', 3], ['T', 69645], ['W', 20019], ['V', 91683], ['Y', 36836], ['X', 1]]

因此，我需要添加的最后一个元素是不添加。我很确定这很简单

预期产出应为：

---

['A'，123885，9.55]，[etc]

如果您只是尝试获取一个嵌套列表，其中每个子列表包含一个键和每个dict中的相应值，那么您可以执行以下操作：

counts = {'A': 123885, 'C': 14983, 'E': 74992, 'D': 66618, 'G': 95475, 'F': 50554, 'I': 77836, 'H': 29255, 'K': 57151, 'M': 36759, 'L': 139002, 'N': 50492, 'Q': 57732, 'P': 57595, 'S': 74803, 'R': 71819, 'U': 3, 'T': 69645, 'W': 20019, 'V': 91683, 'Y': 36836, 'X': 1}  
centages = {'A': 9.550641489186193, 'C': 1.1550814177057491, 'E': 5.781343234104621, 'D': 5.1357681295282385, 'G': 7.360435050087193, 'F': 3.8973493953611724, 'I': 6.000595156413581, 'H': 2.2553498548342583, 'K': 4.405930594894298, 'M': 2.8338542236832165, 'L': 10.71605334204996, 'N': 3.8925696417805975, 'Q': 4.450721511512268, 'P': 4.44015979795519, 'S': 5.766772694963835, 'R': 5.5367277806987385, 'U': 0.0002312783990600846, 'T': 5.369128034179864, 'W': 1.5433207569279443, 'V': 7.068099153675245, 'Y': 2.839790369259092, 'X': 7.709279968669486e-05}

results = [[key, counts[key], centages[key]] for key in counts]

print(results)
# [['A', 123885, 9.550641489186193], ['C', 14983, 1.1550814177057491], ['E', 74992, 5.781343234104621], ['D', 66618, 5.1357681295282385], ['G', 95475, 7.360435050087193], ['F', 50554, 3.8973493953611724], ['I', 77836, 6.000595156413581], ['H', 29255, 2.2553498548342583], ['K', 57151, 4.405930594894298], ['M', 36759, 2.8338542236832165], ['L', 139002, 10.71605334204996], ['N', 50492, 3.8925696417805975], ['Q', 57732, 4.450721511512268], ['P', 57595, 4.44015979795519], ['S', 74803, 5.766772694963835], ['R', 71819, 5.5367277806987385], ['U', 3, 0.0002312783990600846], ['T', 69645, 5.369128034179864], ['W', 20019, 1.5433207569279443], ['V', 91683, 7.068099153675245], ['Y', 36836, 2.839790369259092], ['X', 1, 7.709279968669486e-05]]

---

您还应该包括您的预期输出！感谢您的编辑-更可读！真是太棒了！非常感谢。我知道它必须更简单！

[['A', 123885], ['C', 14983], ['E', 74992], ['D', 66618], ['G', 95475], ['F', 50554], ['I', 77836], ['H', 29255], ['K', 57151], ['M', 36759], ['L', 139002], ['N', 50492], ['Q', 57732], ['P', 57595], ['S', 74803], ['R', 71819], ['U', 3], ['T', 69645], ['W', 20019], ['V', 91683], ['Y', 36836], ['X', 1]]

counts = {'A': 123885, 'C': 14983, 'E': 74992, 'D': 66618, 'G': 95475, 'F': 50554, 'I': 77836, 'H': 29255, 'K': 57151, 'M': 36759, 'L': 139002, 'N': 50492, 'Q': 57732, 'P': 57595, 'S': 74803, 'R': 71819, 'U': 3, 'T': 69645, 'W': 20019, 'V': 91683, 'Y': 36836, 'X': 1}  
centages = {'A': 9.550641489186193, 'C': 1.1550814177057491, 'E': 5.781343234104621, 'D': 5.1357681295282385, 'G': 7.360435050087193, 'F': 3.8973493953611724, 'I': 6.000595156413581, 'H': 2.2553498548342583, 'K': 4.405930594894298, 'M': 2.8338542236832165, 'L': 10.71605334204996, 'N': 3.8925696417805975, 'Q': 4.450721511512268, 'P': 4.44015979795519, 'S': 5.766772694963835, 'R': 5.5367277806987385, 'U': 0.0002312783990600846, 'T': 5.369128034179864, 'W': 1.5433207569279443, 'V': 7.068099153675245, 'Y': 2.839790369259092, 'X': 7.709279968669486e-05}

results = [[key, counts[key], centages[key]] for key in counts]

print(results)
# [['A', 123885, 9.550641489186193], ['C', 14983, 1.1550814177057491], ['E', 74992, 5.781343234104621], ['D', 66618, 5.1357681295282385], ['G', 95475, 7.360435050087193], ['F', 50554, 3.8973493953611724], ['I', 77836, 6.000595156413581], ['H', 29255, 2.2553498548342583], ['K', 57151, 4.405930594894298], ['M', 36759, 2.8338542236832165], ['L', 139002, 10.71605334204996], ['N', 50492, 3.8925696417805975], ['Q', 57732, 4.450721511512268], ['P', 57595, 4.44015979795519], ['S', 74803, 5.766772694963835], ['R', 71819, 5.5367277806987385], ['U', 3, 0.0002312783990600846], ['T', 69645, 5.369128034179864], ['W', 20019, 1.5433207569279443], ['V', 91683, 7.068099153675245], ['Y', 36836, 2.839790369259092], ['X', 1, 7.709279968669486e-05]]