为什么不是'；在if语句中调用的函数是什么？（python）

我最近开始学习编程，尤其是python。我是一个完全的初学者，我开始在我的第一个小项目转换英寸和磅的工作。我不明白为什么函数没有在if语句中被调用。请帮忙！谢谢

# Convert inches to centimeters and pounds to kilograms


# Converts inches to centimeters
def convic():
    amti = raw_input("How many inches? **Integers only!** ")
    if amti.isdigit():
        amti = int(float(amti))
        centi = amti * 2.54
        print "%d inches equals %d centimeters." % (amti, centi)
    else:
        print "Sorry that is not a number and/or integer."

# Converts pounds to kilograms  
def convpk():   
    amtp = raw_input("How many pounds? **Integers only!** ")
    if amtp.isdigit():
        amtp = int(float(amtp))
        kilo = amtp * 0.45359
        print "%d pounds equals %d kilograms." % (amtp, kilo)
    else:
        print "Sorry that is not a number and/or integer."

answer = raw_input("Would you like to convert inches to centimeters or    pounds to kilograms? ")   
if answer == "inches to centimenters":
    convic()
if answer == "pounds to kilograms":
    convpk()

# Not a correct response        
else:
    while answer != "inches to centimeters" and "pounds to kilograms":
        answer = raw_input("Sorry please enter inches to centimeters or  pounds to kilograms. ")
        if answer == "inches to centimenters":
            convic()
        if answer == "pounds to kilograms":
            convpk()

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这一行不是您想要的：

应答时！=“英寸到厘米”和“磅到千克”：

我想你想要：

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应答时！=“英寸到厘米”并回答！=“磅到千克”：

你似乎把厘米拼错了。

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如果你纠正了这一点，那么它应该可以工作。

你有很多If语句，是不是有一个特别的语句导致了这个问题？@user3636636所有包含convic（）或convpk（）的语句@James我的程序没有执行convic（）或convpk（），我只是不知道我做错了什么“英寸到厘米”：额外的nAlso，