Python 为什么我的打印语句没有运行在else下面？

只是一个python初学者。我正在尝试建立一个密码系统，用户可以输入尝试次数来输入密码，或者键入-1进行无限次尝试。密码是999。例如，假设我们为尝试输入密码的次数输入3次尝试。所有的猜测都是错误的。但是，屏幕上没有显示任何内容，而不是打印错误的密码。我该如何解决这个问题？除了上次打印没有显示之外，没有什么不合适的了。

因为打印之前的“继续”从未执行打印

如果与结束条件兼容，continue要求执行for的下一轮

注意：要获得预期的行为，您不仅必须删除else分支中的continue，还必须删除break，以便：

tries=int(input("Enter the number of times you wish to enter the password."))

password=[]

if tries == -1:
    while(True):
        password_guess=int(input("Enter the password (hint: it is an integer): "))
        password.append(password_guess)
        if password_guess == 999:
            print("correct password")
            break
        else:
            continue
else:
    #n=int(input("enter the amount of tries you want to have"))
    password=[0 for x in range(tries)]
    for i in range(tries):
        password[i]=int(input("Enter the password (hint: it is an integer): "))
        if 999 in password:
            print("correct password")
            break
        else:
            continue
            print("incorrect password")
            break

if 999 in password:
    print("correct password")
    break
print("incorrect password")

password[i]=int(input("Enter the password (hint: it is an integer): "))
if 999 in password:

因为then分支有一个断点，所以您也可以执行以下操作：

if 999 in password:
    print("correct password")
    break
else:
    print("incorrect password")

无论如何，我希望：

tries=int(input("Enter the number of times you wish to enter the password."))

password=[]

if tries == -1:
    while(True):
        password_guess=int(input("Enter the password (hint: it is an integer): "))
        password.append(password_guess)
        if password_guess == 999:
            print("correct password")
            break
        else:
            continue
else:
    #n=int(input("enter the amount of tries you want to have"))
    password=[0 for x in range(tries)]
    for i in range(tries):
        password[i]=int(input("Enter the password (hint: it is an integer): "))
        if 999 in password:
            print("correct password")
            break
        else:
            continue
            print("incorrect password")
            break

if 999 in password:
    print("correct password")
    break
print("incorrect password")

password[i]=int(input("Enter the password (hint: it is an integer): "))
if 999 in password:

这很奇怪，因为它足以：

tries=int(input("Enter the number of times you wish to enter the password."))

password=[]

if tries == -1:
    while(True):
        password_guess=int(input("Enter the password (hint: it is an integer): "))
        password.append(password_guess)
        if password_guess == 999:
            print("correct password")
            break
        else:
            continue
else:
    #n=int(input("enter the amount of tries you want to have"))
    password=[0 for x in range(tries)]
    for i in range(tries):
        password[i]=int(input("Enter the password (hint: it is an integer): "))
        if 999 in password:
            print("correct password")
            break
        else:
            continue
            print("incorrect password")
            break

if 999 in password:
    print("correct password")
    break
print("incorrect password")

password[i]=int(input("Enter the password (hint: it is an integer): "))
if 999 in password:

您的初始化：

也很奇怪，因为您可以执行password=[]并替换password[i]=int。。。通过密码。appendint…：

在你的第一个

也没用

因此，您可以：

else:
    continue

当然，您也可以在这两种情况下使用password_guess，或在这两种情况下都使用none来获得相似的代码，或者不使用函数编写两次相同的代码：

tries=int(input("Enter the number of times you wish to enter the password."))

password=[]

if tries == -1:
    while(True):
        password_guess=int(input("Enter the password (hint: it is an integer): "))
        password.append(password_guess)
        if password_guess == 999:
            print("correct password")
            break
else:
    for i in range(tries):
        password.append(int(input("Enter the password (hint: it is an integer): ")))
        if 999 == password[i]:
            print("correct password")
            break
        else:
            print("incorrect password")

print("attempts : ", password)

假设全部在p.py中执行：

---

因为打印之前的“继续”，所以打印永远不会成功executed@AbhinavMathur休息时间不在其他部分谢谢您的回复！但是，每次输入新密码时，这都会给我错误的密码。在计算机以不正确的密码回复之前，如何完成所有错误的尝试？谢谢你的帮助。