Python 在lxml中使用Find函数查找元素
我有下一个xml:Python 在lxml中使用Find函数查找元素,python,xml,lxml,Python,Xml,Lxml,我有下一个xml: <?xml version='1.0' encoding='utf-8'?> <SOAP:Envelope xmlns:SOAP="http://www.w3.org/2003/05/soap-envelope" xmlns:wsa="http://www.w3.org/2005/08/addressing"> <SOAP:Header> </SOAP:Header> <SOAP:Body> &l
<?xml version='1.0' encoding='utf-8'?>
<SOAP:Envelope xmlns:SOAP="http://www.w3.org/2003/05/soap-envelope" xmlns:wsa="http://www.w3.org/2005/08/addressing">
<SOAP:Header>
</SOAP:Header>
<SOAP:Body>
<Server_Reply xmlns="some_url">
<conversionRate>
<conversionRateDetail>
<currency>dollar</currency>
</conversionRateDetail>
</conversionRate>
</Server_Reply>
</SOAP:Body>
</SOAP:Envelope>
我需要找到Server\u Reply元素。
当我这样做时:
response = reply_element.find('Body/Server_Reply')
但它不会返回任何结果。
如何纠正?最后,我需要获取Server\u Reply元素。您需要使用//来指示您要查找的Body是当前元素SOAP:Envelope的后代,而不是直接子元素
而且,由于xml使用名称空间,因此必须在xpath中包含提供给.find的名称空间。范例-
response = reply_xml.find('.//{http://www.w3.org/2003/05/soap-envelope}Body/{some_url}Server_Reply')
或
演示-
In [55]: s = """<SOAP:Envelope xmlns:SOAP="http://www.w3.org/2003/05/soap-envelope" xmlns:wsa="http://www.w3.org/2005/08/addressing">
....: <SOAP:Header>
....: </SOAP:Header>
....: <SOAP:Body>
....: <Server_Reply xmlns="some_url">
....: <conversionRate>
....: <conversionRateDetail>
....: <currency>dollar</currency>
....: </conversionRateDetail>
....: </conversionRate>
....: </Server_Reply>
....: </SOAP:Body>
....: </SOAP:Envelope>"""
In [56]: reply_xml = etree.fromstring(s)
In [57]: reply_xml.find('.//SOAP:Body/dummy:Server_Reply',namespaces = {'SOAP':'http://www.w3.org/2003/05/soap-envelope', 'dummy':'some_url'})
Out[57]: <Element {some_url}Server_Reply at 0x481d708>
In [58]: reply_xml.find('.//{http://www.w3.org/2003/05/soap-envelope}Body/{some_url}Server_Reply')
Out[58]: <Element {some_url}Server_Reply at 0x481d708>
我发现xpath更加直观和简单:
from lxml import etree
xml = """<?xml version='1.0' encoding='utf-8'?>
<SOAP:Envelope xmlns:SOAP="http://www.w3.org/2003/05/soap-envelope" xmlns:wsa="http://www.w3.org/2005/08/addressing">
<SOAP:Header>
</SOAP:Header>
<SOAP:Body>
<Server_Reply xmlns="some_url">
<conversionRate>
<conversionRateDetail>
<currency>dollar</currency>
</conversionRateDetail>
</conversionRate>
</Server_Reply>
</SOAP:Body>
</SOAP:Envelope>"""
et = etree.fromstring(xml)
server_reply = et.xpath('//*[local-name()="Server_Reply"]')
使用xml.etree来执行此操作
#!/usr/bin/env python
import sys
from xml.etree import ElementTree
from lxml import etree
def run(fileName):
parser = etree.XMLParser(ns_clean=True)
data = ElementTree.parse(fileName, parser).getroot()
namespaces = data.nsmap
namespaces['some_url'] = 'some_url'
# Creating without duplicates here, which contains the unique list of elements determined by values of subelements
for row in data.findall('.//SOAP:Body/some_url:Server_Reply', namespaces = namespaces):
print row
if __name__ == "__main__":
run(sys.argv[1])
然后以XML文件作为参数运行python:
python findElement.py sampleFile.xml
很高兴知道投票被否决的原因。
#!/usr/bin/env python
import sys
from xml.etree import ElementTree
from lxml import etree
def run(fileName):
parser = etree.XMLParser(ns_clean=True)
data = ElementTree.parse(fileName, parser).getroot()
namespaces = data.nsmap
namespaces['some_url'] = 'some_url'
# Creating without duplicates here, which contains the unique list of elements determined by values of subelements
for row in data.findall('.//SOAP:Body/some_url:Server_Reply', namespaces = namespaces):
print row
if __name__ == "__main__":
run(sys.argv[1])
python findElement.py sampleFile.xml