删除python中的括号及其内容

我使用lstm方法实现了一个情绪分析分类。我已经训练了我的模型并保存了它。我已经加载了列车模型，我正在做分类部分，在那里我将它保存在一个数据帧中。我需要删除括号及其内容，我将在下面向您展示

这是我的密码：

 hotelname = []
sentimentanalysis = []

for item in selection1:
    name = item['name']
    hotelname.append(name)
    print (name)

结果如下：

Mystik Lifestyle (Save 34%)
Chalets Chamarel (Adults Only)
Andrea Lodge (Save 18%)
Hibiscus Beach Resort & Spa (Save 18%)
Lagoon Attitude (Adults Only)
Ocean V Hotel (Adults Only)

但我希望我的输出是这样的：：

Mystik Lifestyle 
Chalets Chamarel 
Andrea Lodge 
Hibiscus Beach Resort & Spa 
Lagoon Attitude 
Ocean V Hotel 

---

有人能告诉我我需要在代码中添加什么吗伙计们。

你们可以使用

re

模块实现以下目的：

import re
def clean(n):
    return re.sub(r'\s\(.*\)','',n)

然后：

而不是

name = item['name']

请注意，我使用所谓的原始字符串作为re.sub的第一个参数，并删除括号及其内容之前的空白（

\s

）。请注意，

（

和

）

需要转义，因为它们在模式中具有特殊意义（因此导致反斜杠）

---

编辑：

li = ['Mystik Lifestyle (Save 34%)',
'Chalets Chamarel (Adults Only)',
'Andrea Lodge (Save 18%)',
'Hibiscus Beach Resort & Spa (Save 18%)',
'Lagoon Attitude (Adults Only)',
'Ocean V Hotel (Adults Only)']

for i in li:
    cleaned_text = remove_bracket(i)
    print(cleaned_text)

Mystik Lifestyle
Chalets Chamarel
Andrea Lodge
Hibiscus Beach Resort & Spa
Lagoon Attitude
Ocean V Hotel

输出：

li = ['Mystik Lifestyle (Save 34%)',
'Chalets Chamarel (Adults Only)',
'Andrea Lodge (Save 18%)',
'Hibiscus Beach Resort & Spa (Save 18%)',
'Lagoon Attitude (Adults Only)',
'Ocean V Hotel (Adults Only)']

for i in li:
    cleaned_text = remove_bracket(i)
    print(cleaned_text)

Mystik Lifestyle
Chalets Chamarel
Andrea Lodge
Hibiscus Beach Resort & Spa
Lagoon Attitude
Ocean V Hotel

---

您可以使用名为.split（）的简单字符串方法
请看下面的代码：

elements = ['Mystik Lifestyle (Save 34%)',
'Chalets Chamarel (Adults Only)',
'Andrea Lodge (Save 18%)',
'Hibiscus Beach Resort & Spa (Save 18%)',
'Lagoon Attitude (Adults Only)',
'Ocean V Hotel (Adults Only)']

for element in elements:
    without_text_after_unwanted_character = element.split('(')[0] 
    # This will get everything before the '(' as we splitted
    print(without_text_after_unwanted_character)

# If you want to create a new list the new values, you can do:
clean_list = [x.split('(')[0] for x in elements]

for clean_text in clean_list:
    print(clean_text)

---

您可以尝试以下代码：

hotelname = []
sentimentanalysis = []

for item in selection1:
    name = item['name'].split('(')[0].strip()
    hotelname.append(name)
    print (name)

---

一种方法是用“（”分开，然后取第一个元素（如果有的话），我不明白，女士。你能解释一下吗？还是一样的先生还是一样的Madamp打印你的酒店名称，直到同一个Madamp请与我们分享屏幕快照。

hotelname = []
sentimentanalysis = []

for item in selection1:
    name = item['name'].split('(')[0].strip()
    hotelname.append(name)
    print (name)