Python while循环测试两个true/false元素

我正在为我的孩子们做一个单词拼图游戏。我希望他们能够在猜测中键入“hint”以获得提示。第一个“提示”应该给出单词的第一个和最后一个字母。下次他们键入“hint”时，应提供单词的前两个和后两个字母。。等等

我让它第一次工作，他们键入'提示'，但随后while循环被打破，他们不能猜错或再次键入'提示'

我知道问题在于这一行：

while guess != correct and guess != 'hint':

我似乎无法修复它，以便用户可以多次键入提示

这是我的密码：

# The computer picks a random word, and then "jumbles" it
# the player has to guess the original word

import random

replay = "y"
while replay == "y":

    print("\n"* 100)
    word = input("Choose a word for your opponent to de-code: ")
    print("\n"* 100)
    # provide a hint if the user wants one
    hint_count = 1

    # create a variable to use later to see if the guess is correct
    correct = word

    # create a empty jumble word
    jumble = ""
    # while the chosen word has letters in it
    while word:
        position = random.randrange(len(word))
    #   add the random letter to the jumble word
        jumble += word[position]
    #   extract a random letter from the chosen word
        word = word[:position] + word[position +1:]

    # start the game
    print(
    """

                Welcome to the Word Jumble!

        Unscramble the letters to make a word.
    (Press the enter key at the prompt to quit.)
    """
    )
    score = 10
    print("The jumble is: ",jumble)

    guess = input("\nType 'hint' for help but lose 3 points. \
                  \nYOUR GUESS: ")

    while guess != correct and guess != 'hint':
        print("Sorry that's not it.")
        score -= 1
        guess = input("Your guess: ")

    if guess == 'hint':
        print("The word starts with '"+ correct[0:hint_count]+"' and ends with '"+correct[len(correct)-hint_count:len(correct)]+"'")
        score -= 3
        hint_count += 1
        guess = input("Your guess: ")

    if guess == correct:
        print("That's it! You guessed it!\n")
        print("Your score is ",score)


    print("Thanks for playing.")

    replay = input("\n\nWould you like to play again (y/n).")

---

问题是您在while循环之外检查

guess==“hint”

。试试像这样的东西

while True:
    guess = input(...)
    if guess == correct:
        # correct
        break
    elif guess == 'hint':
        # show hint
    else:
        # not it, decrement score

---

问题是您在while循环之外检查

guess==“hint”

。试试像这样的东西

while True:
    guess = input(...)
    if guess == correct:
        # correct
        break
    elif guess == 'hint':
        # show hint
    else:
        # not it, decrement score

---

在第一个“提示”之后，程序应该询问猜测，然后继续打印（“感谢播放”），因为检查提示的条件在while循环之外。将其放入while循环：

while guess != correct:
    if guess == 'hint':
        print("The word starts with '"+ correct[0:hint_count]+"' and ends with '"+correct[len(correct)-hint_count:len(correct)]+"'")
        score -= 3
        hint_count += 1
        guess = input("Your guess: ")

     else:
        print("Sorry that's not it.")
        score -= 1
        guess = input("Your guess: ")

---

在第一个“提示”之后，程序应该询问猜测，然后继续打印（“感谢播放”），因为检查提示的条件在while循环之外。将其放入while循环：

while guess != correct:
    if guess == 'hint':
        print("The word starts with '"+ correct[0:hint_count]+"' and ends with '"+correct[len(correct)-hint_count:len(correct)]+"'")
        score -= 3
        hint_count += 1
        guess = input("Your guess: ")

     else:
        print("Sorry that's not it.")
        score -= 1
        guess = input("Your guess: ")

---

顺便说一句，有更简单的方法来创建混乱。顺便说一句，有更简单的方法来创建混乱。查看。您的问题是

while

循环允许用户输入猜测或

hint

，但输入

hint

会中断循环。这就是为什么用户只能使用

hint

一次（在一次提示之后，用户只能再输入一个单词）。现在有几个答案，其中任何一个都可以解决这个问题。您需要一个

while

循环，直到用户正确获得单词后才会退出，并且您希望对用户键入的每个答案分别进行评估（是否正确？是否为

提示

？是否为

退出

？），这是一个逻辑问题，不是编程问题。@KarlKnechtel编程本身就是一个逻辑问题。您的问题是，

while

循环允许用户输入猜测或

hint

，但输入

hint

会中断循环。这就是为什么用户只能使用

hint

一次（在一次提示之后，用户只能再输入一个单词）。现在有几个答案，其中任何一个都可以解决这个问题。您需要一个

while

循环，直到用户正确获得单词后才会退出，并且您希望对用户键入的每个答案分别进行评估（是否正确？是否为

提示

？是否为

退出

？），这是一个逻辑问题，不是编程问题。@KarlKnechtel编程本身就是一个逻辑问题。