如何在嵌入式python解释器中查看日志输出?
我在iOS应用程序中使用嵌入式python解释器。我可以在Xcode控制台中看到如何在嵌入式python解释器中查看日志输出?,python,logging,interpreter,Python,Logging,Interpreter,我在iOS应用程序中使用嵌入式python解释器。我可以在Xcode控制台中看到打印输出,但看不到任何logging.info()或logging.debug()输出。我如何启用它 我的测试python代码: import logging import sys # try to add logging output to stdout logging.basicConfig() log = logging.getLogger() log.addHandler(logging.StreamHa
打印
输出,但看不到任何logging.info()
或logging.debug()
输出。我如何启用它
我的测试python代码:
import logging
import sys
# try to add logging output to stdout
logging.basicConfig()
log = logging.getLogger()
log.addHandler(logging.StreamHandler())
log.addHandler(logging.StreamHandler(sys.stdout))
# for calling from outside
def main__(args):
print("main__()") # can see output
print type(args)
print len(args)
for eachArg in args:
# print('#: %s' % eachArg) # can see output
logging.info(eachArg) # can NOT see output
输出为:
main__()
<type 'list'>
281
main
281
我认为这些东西处于调试级别。
此代码适用于我:
import logging
import sys
log = logging.getLogger()
log.setLevel(logging.DEBUG)
stream = logging.StreamHandler(sys.stdout)
stream.setLevel(logging.DEBUG)
log.addHandler(stream)
# for calling from outside
def main__(args):
print("main__()") # can see output
print type(args)
print len(args)
for eachArg in args:
logging.info(eachArg)
输出:
>>> main__('test')
main__()
<type 'str'>
4
t
e
s
t
>>>
>>main(测试)
主要的
4.
T
E
s
T
>>>
你完全正确!我希望logging.INFO
是默认的日志记录级别,但这是错误的。使用log.setLevel(logging.DEBUG)
。顺便说一句,我发现设置处理程序的日志级别不是必需的