基于joblib的python简单并行计算

我举了一个例子。下面是我的代码的样子：

from math import sqrt
from joblib import Parallel, delayed
import multiprocessing

test = Parallel(n_jobs=2)(delayed(sqrt)(i ** 2) for i in range(10))
print(test)

它会产生以下错误消息：

Attempting to do parallel computing without protecting your import
on a system that does not support forking. To use parallel-computing 
in a script, you must protect you main loop using 
"if __name__ == '__main__'". Please see the joblib documentation on 
Parallel for more information

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而且它运行的时间太长了。我遗漏了什么？

错误消息和BrenBran告诉您的是a）您应该阅读错误消息，b）您应该将代码组织为：

from math import sqrt
from joblib import Parallel, delayed
import multiprocessing

if __name__ == '__main__':
    test = Parallel(n_jobs=2)(delayed(sqrt)(i ** 2) for i in range(10))
    print(test)

嗯

---

barny

错误消息和BrenBran告诉您的是：a）您应该阅读错误消息，b）您应该组织代码，如下所示：

from math import sqrt
from joblib import Parallel, delayed
import multiprocessing

if __name__ == '__main__':
    test = Parallel(n_jobs=2)(delayed(sqrt)(i ** 2) for i in range(10))
    print(test)

嗯 巴尼

我必须将backend=“threading”添加到巴尼的代码中才能正常运行：

from math import sqrt
from joblib import Parallel, delayed
import multiprocessing

if __name__ == '__main__':
    test = Parallel(n_jobs=2, backend="threading")(delayed(sqrt)(i ** 2) for i in range(10))
print(test)

我必须将backend=“threading”添加到barny的代码中，才能正常运行：

from math import sqrt
from joblib import Parallel, delayed
import multiprocessing

if __name__ == '__main__':
    test = Parallel(n_jobs=2, backend="threading")(delayed(sqrt)(i ** 2) for i in range(10))
print(test)

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您是否阅读了错误消息告诉您要阅读的文档？您是否阅读了错误消息告诉您要阅读的文档？我正在审阅文档，如果我们使用backend=“threading”，则可能导致python的全局解释器锁定。我正在审阅文档，如果我们使用backend=“threading”然后可能导致python的全局解释器锁。