Python Django模型，如何添加用户而不是实例？

我试图返回一个JSON格式，但得到一个错误，用户对象不可JSON序列化

我进行了调试并发现了问题，但我一直在修复它

现在如果我打印我的对象，我会得到这样的格式

[
    {
    'id': 1,
    'poster': <User: stackoverflow>,
    'description': 'test',
    'date_added': 'Apr 20 2021, 02:52 AM',
    'likes': 1
    }
]

views.py-创建新对象的函数

@csrf_exempt
def compose_post(request):
    # Composing a new post must be via POST
    if request.method != "POST":
        return JsonResponse({"error": "POST request required."}, status=400)

    # Check post words
    data = json.loads(request.body)
    words = [word.strip() for word in data.get("description").split(" ")]
    if words == [""]:
        return JsonResponse({
            "error": "At least one word required."
        }, status=400)

    # Convert post to NewPost object
    description = data.get("description", "")

    new_post = NewPost(poster=request.user, description=description)
    new_post.save()
    return JsonResponse({"message": "Post saved successfully."}, status=201)

---

由于函数返回dict，您可以使用：

NewPost.serialize（）['poster']

或者可能：

NewPost.objects.get（id=id）['poster']

我找到了解决方案，似乎我不理解类中的serialize方法。我编辑为“poster”：self.poster.username，所以现在当我循环时，我将用户名作为字符串而不是实例返回

@csrf_exempt
def compose_post(request):
    # Composing a new post must be via POST
    if request.method != "POST":
        return JsonResponse({"error": "POST request required."}, status=400)

    # Check post words
    data = json.loads(request.body)
    words = [word.strip() for word in data.get("description").split(" ")]
    if words == [""]:
        return JsonResponse({
            "error": "At least one word required."
        }, status=400)

    # Convert post to NewPost object
    description = data.get("description", "")

    new_post = NewPost(poster=request.user, description=description)
    new_post.save()
    return JsonResponse({"message": "Post saved successfully."}, status=201)