Python 极坐标图在matplotlib中给出了错误的角度

我试图用Python绘制一个赤经-赤纬，极坐标图，其中角度表示赤经，赤纬半径在±30之间

我的代码是

import numpy
import matplotlib.pyplot as pyplot

ra = [345.389547454166689,31.892236646759279,45.893722479722229,93.955296573703706,160.079453957685217,211.154701609814822,256.486559377222193,307.258751710462889,299.691923545370344,340.364168244814834,335.077343971296386,358.126565808425880]
dec = [23.835021447037050,25.218513920000003,27.509148433518519,26.551432991388879,-25.077519630833340,-20.134061982500004,-21.042512836851849,-4.903512838240742,-0.506450475370370,14.280932901944448,19.222101837500002,18.792707990925926]   

fig = pyplot.figure()
ax = fig.add_axes([0.1,0.1,0.8,0.8],polar=True)
ax.set_ylim(-30,30)
ax.set_yticks(numpy.arange(-30,30,10))
ax.scatter(ra,dec,c ='r')


pyplot.show()    

这将生成以下图表：

很明显，我误解了极坐标图的工作原理，因为RA与θ=0的圆角不对应。例如，我的一个点的RA=45.89度，但似乎没有一个点与此对应

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关于我做错了什么有什么建议吗？

绘图需要弧度。添加以下行并重新填充将正确显示：

ra  = [x/180.0*3.141593 for x in ra]

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绘图需要弧度。添加以下行并重新填充将正确显示：

ra  = [x/180.0*3.141593 for x in ra]