Python 为什么Flask服务器避免打开特定端口?
当我指定一个IP和端口时,没有前面的说明:Python 为什么Flask服务器避免打开特定端口?,python,flask,Python,Flask,当我指定一个IP和端口时,没有前面的说明: if __name__ == '__main__': 因此: app.run(host="138.165.91.210",port=5017,threaded=True) 它工作,但它挂起一点(它是否挂在无限循环上?)。当我照常做的时候: if __name__ == '__main__': app.run(host="138.165.91.210",port=5017,threaded=True) 它避免了ip和端口。我的代码怎么了
if __name__ == '__main__':
因此:
app.run(host="138.165.91.210",port=5017,threaded=True)
它工作,但它挂起一点(它是否挂在无限循环上?)。当我照常做的时候:
if __name__ == '__main__':
app.run(host="138.165.91.210",port=5017,threaded=True)
它避免了ip和端口。我的代码怎么了
完整脚本:
import os
from sqlite3 import dbapi2 as sqlite3
from flask import Flask, request, session, g, redirect, url_for, abort, \
render_template, flash
# create our little application :)
app = Flask(__name__)
# Load default config and override config from an environment variable
def connect_db():
"""Connects to the specific database."""
rv = sqlite3.connect(app.config['DATABASE'])
rv.row_factory = sqlite3.Row
return rv
def init_db():
"""Initializes the database."""
db = get_db()
with app.open_resource('schema.sql', mode='r') as f:
db.cursor().executescript(f.read())
db.commit()
@app.cli.command('initdb')
def initdb_command():
"""Creates the database tables."""
init_db()
print('Initialized the database.')
def get_db():
"""Opens a new database connection if there is none yet for the
current application context.
"""
if not hasattr(g, 'sqlite_db'):
g.sqlite_db = connect_db()
return g.sqlite_db
@app.teardown_appcontext
def close_db(error):
"""Closes the database again at the end of the request."""
if hasattr(g, 'sqlite_db'):
g.sqlite_db.close()
@app.route('/')
def show_entries():
db = get_db()
cur = db.execute('select title, text from entries order by id desc')
entries = cur.fetchall()
return render_template('show_entries.html', entries=entries)
@app.route('/add', methods=['POST'])
def add_entry():
if not session.get('logged_in'):
abort(401)
db = get_db()
db.execute('insert into entries (title, text) values (?, ?)',
[request.form['title'], request.form['text']])
db.commit()
flash('New entry was successfully posted')
return redirect(url_for('show_entries'))
@app.route('/login', methods=['GET', 'POST'])
def login():
error = None
if request.method == 'POST':
if request.form['username'] != app.config['USERNAME']:
error = 'Invalid username'
elif request.form['password'] != app.config['PASSWORD']:
error = 'Invalid password'
else:
session['logged_in'] = True
flash('You were logged in')
return redirect(url_for('show_entries'))
return render_template('login.html', error=error)
@app.route('/logout')
def logout():
session.pop('logged_in', None)
flash('You were logged out')
return redirect(url_for('show_entries'))
@app.route("/hello")
def hello():
return "Hello World!"
if __name__ == '__main__':
app.run(host="138.165.91.210",port=5017,threaded=True)
编辑:
我正在使用bash
运行应用程序:
flask --app=flaskr run
您使用的是Flask的未发布版本,因此请记住,情况可能会发生变化
\uuuuu name\uuuu='\uuuuuu main\uuuuu'
仅在直接执行文件时计算为True(即,python filename.py
)。因为这不是您在这里运行它的方式,所以它将为False,并跳过该块
要解决端口问题,在使用flask
命令运行应用程序时,需要通过命令行指定选项
python -m flask --app flaskr --host 138.165.91.210 --port 5017 --with-threads
有关更多信息,请检查用法
python -m flask --help
为了解决延迟问题,if uuuu name uuu=='uuuu main uuu':块很重要。没有它,Flask将尝试运行应用程序的两个实例(一个来自
Flask
命令,另一个来自调用app.run
).您如何运行应用程序?请注意,只有在直接运行脚本时,\uuu name\uuu
==“main”。@dirn from bash:flask--app=flaskrrun@EugeneSoldatov这是什么意思?推荐阅读: