Python 如何合并两个长度不等的列表？

我有两个列表，一个是城市列表，另一个是州列表

以下是我的城市列表：

print(combined_city_list)
[['Los Angeles', 'Long Beach', 'Anaheim'], ['Dallas', 'Fort Worth'], ['Miami', 'Fort Lauderdale'], ['Minneapolis', 'St Paul'], ['Louisville', 'Jefferson County'], ['North Port', 'Sarasota', 'Bradenton'], ['Winston', 'Salem'], ['Santa Maria', 'Santa Barbara'], ['Crestview', 'Fort Walton Beach', 'Destin'], ['Macon', 'Bibb County'], ['Champaign', 'Urbana'], ['Lafayette', 'West Lafayette'], ['California', 'Lexington Park'], ['Pinehurst', 'Southern Pines'], ['Hermiston', 'Pendleton'], ['Wisconsin Rapids', 'Marshfield'], ['Arkansas City', 'Winfield']]

print(combined_state_list)
[[' CA'], [' TX'], [' FL'], [' MN'], [' KY'], [' FL'], [' NC'], [' CA'], [' FL'], [' GA'], [' IL'], [' IN'], [' MD'], [' NC'], [' OR'], [' WI'], [' KS']]

以下是我的状态列表：

print(combined_city_list)
[['Los Angeles', 'Long Beach', 'Anaheim'], ['Dallas', 'Fort Worth'], ['Miami', 'Fort Lauderdale'], ['Minneapolis', 'St Paul'], ['Louisville', 'Jefferson County'], ['North Port', 'Sarasota', 'Bradenton'], ['Winston', 'Salem'], ['Santa Maria', 'Santa Barbara'], ['Crestview', 'Fort Walton Beach', 'Destin'], ['Macon', 'Bibb County'], ['Champaign', 'Urbana'], ['Lafayette', 'West Lafayette'], ['California', 'Lexington Park'], ['Pinehurst', 'Southern Pines'], ['Hermiston', 'Pendleton'], ['Wisconsin Rapids', 'Marshfield'], ['Arkansas City', 'Winfield']]

print(combined_state_list)
[[' CA'], [' TX'], [' FL'], [' MN'], [' KY'], [' FL'], [' NC'], [' CA'], [' FL'], [' GA'], [' IL'], [' IN'], [' MD'], [' NC'], [' OR'], [' WI'], [' KS']]

这就是我尝试过的：

combined_state_short = [i[0] for i in combined_state_list]

combined_city_state = []
for c, s in zip (combined_city_list, combined_state_list):
    for i in c:
        combined_city_state = str(i) + ',' + str(s)

print(combined_city_state)

我将此作为输出：

Winfield,[' KS']

我想要这样的东西：

['Los Angeles, CA', 'Long Beach, CA' ...]

就你而言

newlist = [z + ',' + y[0]  for x , y in zip(combined_city_list,combined_state_list) for z in x]

就你而言

newlist = [z + ',' + y[0]  for x , y in zip(combined_city_list,combined_state_list) for z in x]

这将有助于：

[city + ',' + state for (cities, (state, *_)) in zip(combined_city_list, combined_state_list) for city in cities]

这将有助于：

[city + ',' + state for (cities, (state, *_)) in zip(combined_city_list, combined_state_list) for city in cities]

---

对于这种形式的初学者可能更清楚：

new_list = []
for cities, state in zip(combined_city_list, combined_state_list):
    for city in cities:
        new_list.append(city + ',' + state[0])
new_list

---

对于这种形式的初学者可能更清楚：

new_list = []
for cities, state in zip(combined_city_list, combined_state_list):
    for city in cities:
        new_list.append(city + ',' + state[0])
new_list

---

每个州仍然有子列表。我认为需要一个简单的列表。@JosephSible如果是这样的话，只需将第二个for循环移到末尾：-）谢谢你们！我刚刚意识到我已经覆盖了我的组合城市州列表，只需要添加一个中间变量来追加。@Lee无论如何，问题得到了解决：-）happy Coding每个州都有子列表。我认为需要一个简单的列表。@JosephSible如果是这样的话，只需将第二个for循环移到末尾：-）谢谢你们！我刚刚意识到我已经覆盖了我的组合城市州列表，只需要添加一个中间变量来追加。@Lee不管怎样，问题得到了解决：-）快乐编码