Python 输入验证并将元组列表转换为txt文件

我正在尝试将元组列表转换为txt文件，并对两个输入进行输入验证。顺便说一句，我试图做它没有和CSV模块。 我得到了这个元组列表：

list1 = [(16, 'Peter' , 2005) , (21, 'Philip', 2000) , (10, 'Kate', 2011)]

我想把它转换成一个txt文件，如下所示：

Age      Name     YOB
16       Peter    2005
21       Philip   2000
10       Kate     2011

我需要对输入进行验证，确认第一个输入是一个列表，第二个输入是一个字符串。文件行应该用制表符分隔

def my_func(list1,new_file):
   header = "Age, Name, YOB"
   if isinstance(list1, list):
      for i in list1:
        if isinstance(list1[i], str):
            with open("Age_file.txt", "w") as output:
                output.write(header + "\n")
                output.close()
                with open("Age_file.txt", "w") as output:
                    for i in output:
                        output.write(str(i) + "\n")
        else:
            "Second input must be a str."
else:
    "First input must be a list."

但我得到这个类型错误：

'''
if isinstance(list1[i], str):
TypeError: list indices must be integers or slices, not tuple
'''

---

谢谢你的帮助，谢谢

这里的问题是，第二个

for

循环中的

i

是一个

元组，如回溯中所述。实际上，您正在尝试执行以下操作，以避免出现错误：

list1[(16, 'Peter' , 2005)]

听起来您希望确保每个元组的第二项是
str
，在这种情况下，您的代码应该如下所示。我还对其进行了修改，使您只打开一次文件，而不是每次迭代都打开一次，然后继续使用
new_file
param，您似乎根本没有使用它

def my_func(list1, new_file):
    if not isinstance(list1, list):
        raise ValueError("First argument must be a list!")
    header = "Age, Name, YOB"
    with open(new_file, "w") as output:
        output.write(header + "\n")
        for line in list1:
            if not isinstance(line[1], str):
                raise ValueError("Second item in each tuple must be a str!")
            
            vals = ",".join(str(i) for i in line)
            output.write(vals + "\n")

你有没有试着做三个独立的元组列表？然后你只有一个字符串列表和两个数字列表。。。然后你可以把：

list1 = [16, 21, 10]
list2 = ['Peter', 'Philipp', 'Kate']
list3 = [2005, 2000, 2010]
listfull = list(zip(list1, list2, list3))


然后您可以从这些列表中创建一个数据帧：

df = pd.DataFrame(listfull, columns =['Age', 'Name', 'YOB'])

然后你可以将其作为文本或csv文件保存。。。
我不确定这是否有帮助

df.to_csv('df.csv')

下面的评论中提到了代码失败的原因：

list1 = [(16, 'Peter' , 2005) , (21, 'Philip', 2000) , (10, 'Kate', 2011)]
# list1 is a list of tuples here

def my_func(list1,new_file):
    #assuming we are getting same list1 defined above list1 is still list of tuples
    header = "Age, Name, YOB"
    if isinstance(list1, list):
        for i in list1:
            # i should be tuples like (16, 'Peter' , 2005)
            if isinstance(list1[i], str): # error thrown because i is tuple
                with open("Age_file.txt", "w") as output:
                    output.write(header + "\n")
                    output.close()
                    with open("Age_file.txt", "w") as output:
                        for i in output:
                            output.write(str(i) + "\n")
            else:
                "Second input must be a str."
    else:
        "First input must be a list."
        

您可以尝试以下代码：

list1 = [(16, 'Peter' , 2005) , (21, 'Philip', 2000) , (10, 'Kate', 2011)]
# list1 is a list of tuples here


def my_func(list1,new_file):
    if not isinstance(list1, list):
        raise Exception("list1 must be a list") # exception thrown in case list1 is not a list
    if not isinstance(new_file, str):
        raise Exception("new_file must be a str") # exception thrown in case new file is not a str.
        # However in your code it is not clear what is the purpose of argument new_file
    result = "Age\tName\tYOB\n" # \t for tab. tab is better than space is it somewhat maintains indentation of the columns
    for list2 in list1:
        result += "\t".join([str(x) for x in list2]) + "\n"
        # list comprehension used to convert all item in tuple list2 to strings
    with open("Age_file.txt", "w") as output:
        output.write(result.strip())


my_func(list1, "test")

这一定是一个元组列表，我想在不使用pandaThats之类的模块的情况下完成它！我明白你说的话了。这真是信息量大，对理解过程有很大帮助，谢谢！