Python 如何使用BeautifulSoup提取span h5 a href链接中的标题

我正在尝试使用BeautifulSoup提取链接的标题。我使用的代码如下所示：

import requests
from bs4 import BeautifulSoup
from urllib.parse import urljoin
import pandas as pd

hdr={'User-Agent':'Chrome/84.0.4147.135'}

frame=[]

for page_number in range(19):
    http= "https://www.epa.wa.gov.au/media-statements?page={}".format(page_number+1)

    print('Downloading page %s...' % http)

    url= requests.get(http,headers=hdr)
    soup = BeautifulSoup(url.content, 'html.parser')

    for row in soup.select('.view-content .views-row'):

        content = row.select_one('.views-field-body').get_text(strip=True)
        title = row.text.strip(':')
        link = 'https://www.epa.wa.gov.au' + row.a['href']
        date = row.select_one('.date-display-single').get_text(strip=True)

        frame.append({
        'title': title,
        'link': link,
        'date': date,
        'content': content
    })

dfs = pd.DataFrame(frame)
dfs.to_csv('epa_scrapper.csv',index=False,encoding='utf-8-sig')

但是，在运行上述代码后，不会显示任何内容。如何提取存储在link中的锚定标记的title属性中的值

另外，我只想知道如何将“标题”、“链接”、“dt”、“内容”附加到csv文件中

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提前非常感谢。

要获取链接文本，您可以使用选择器

“h5 a”

。例如：

import requests
from bs4 import BeautifulSoup
from urllib.parse import urljoin
import pandas as pd

hdr={'User-Agent':'Chrome/84.0.4147.135'}

frame=[]
for page_number in range(1, 20):
    http= "https://www.epa.wa.gov.au/media-statements?page={}".format(page_number)

    print('Downloading page %s...' % http)

    url= requests.get(http,headers=hdr)
    soup = BeautifulSoup(url.content, 'html.parser')

    for row in soup.select('.view-content .views-row'):

        content = row.select_one('.views-field-body').get_text(strip=True, separator='\n')
        title = row.select_one('h5 a').get_text(strip=True)
        link = 'https://www.epa.wa.gov.au' + row.a['href']
        date = row.select_one('.date-display-single').get_text(strip=True)

        frame.append({
            'title': title,
            'link': link,
            'date': date,
            'content': content
        })

dfs = pd.DataFrame(frame)
dfs.to_csv('epa_scrapper.csv',index=False,encoding='utf-8-sig')

创建

epa_scraster.csv

（来自LibreOffice的屏幕截图）：

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非常感谢您的回复。我对Python还很陌生，所以我有点搞砸了。真的非常感谢你！