Python 通过控制台操作从目录中的所有文件名中删除多个字符串
我想知道重命名目录中所有文件的最简单方法是什么 我有如下文件名:Python 通过控制台操作从目录中的所有文件名中删除多个字符串,python,string,bash,file-rename,Python,String,Bash,File Rename,我想知道重命名目录中所有文件的最简单方法是什么 我有如下文件名: output_original_2018_0729_112557_065.JPG_7c82d91a-6a2a-4f9f-a9ed-ccbc34afe7a9.JPG output_original_2018_0729_112557_065.JPG_15f07152-76d0-4834-993b-2ca8f589310f.JPG output_original_2018_0729_112631_070.JPG_cd08da59-0de
output_original_2018_0729_112557_065.JPG_7c82d91a-6a2a-4f9f-a9ed-ccbc34afe7a9.JPG
output_original_2018_0729_112557_065.JPG_15f07152-76d0-4834-993b-2ca8f589310f.JPG
output_original_2018_0729_112631_070.JPG_cd08da59-0de7-4a94-b769-5450fb80e982.JPG
现在我想删除前导部分和结尾部分,如果文件名相同,还想使用计数器重命名文件本身。这会导致这样的结果:
2018_0729_112557_065_1.JPG
2018_0729_112557_065_2.JPG
2018_0729_112631_070.JPG
提前谢谢
编辑:我试着用正则表达式删除第一部分:
for file in *; do echo mv ./"$file" ./"$(echo "$file" | cut -c17-)";
不完全是计数器方面的要求,但我没有时间修复它:
import re
import os
filenames = [
'output_original_2018_0729_112557_065.JPG_7c82d91a-6a2a-4f9f-a9ed-ccbc34afe7a9.JPG',
'output_original_2018_0729_112557_065.JPG_15f07152-76d0-4834-993b-2ca8f589310f.JPG',
'output_original_2018_0729_112631_070.JPG_cd08da59-0de7-4a94-b769-5450fb80e982.JPG',
]
new_filenames = set()
for filename in filenames:
base_filename = new_filename = re.match(
r'output_original_(.+?)\.JPG',
filename,
).group(1)
count = 1
while new_filename in new_filenames:
new_filename = "{base_filename}_{count}".format(**locals())
count += 1
new_filenames.add(new_filename)
new_filename += ".JPG"
print(filename, '->', new_filename)
os.rename(filename, new_filename)
输出:
output_original_2018_0729_112557_065.JPG_7c82d91a-6a2a-4f9f-a9ed-ccbc34afe7a9.JPG -> 2018_0729_112557_065.JPG
output_original_2018_0729_112557_065.JPG_15f07152-76d0-4834-993b-2ca8f589310f.JPG -> 2018_0729_112557_065_1.JPG
output_original_2018_0729_112631_070.JPG_cd08da59-0de7-4a94-b769-5450fb80e982.JPG -> 2018_0729_112631_070.JPG
不完全是计数器方面的要求,但我没有时间修复它:
import re
import os
filenames = [
'output_original_2018_0729_112557_065.JPG_7c82d91a-6a2a-4f9f-a9ed-ccbc34afe7a9.JPG',
'output_original_2018_0729_112557_065.JPG_15f07152-76d0-4834-993b-2ca8f589310f.JPG',
'output_original_2018_0729_112631_070.JPG_cd08da59-0de7-4a94-b769-5450fb80e982.JPG',
]
new_filenames = set()
for filename in filenames:
base_filename = new_filename = re.match(
r'output_original_(.+?)\.JPG',
filename,
).group(1)
count = 1
while new_filename in new_filenames:
new_filename = "{base_filename}_{count}".format(**locals())
count += 1
new_filenames.add(new_filename)
new_filename += ".JPG"
print(filename, '->', new_filename)
os.rename(filename, new_filename)
输出:
output_original_2018_0729_112557_065.JPG_7c82d91a-6a2a-4f9f-a9ed-ccbc34afe7a9.JPG -> 2018_0729_112557_065.JPG
output_original_2018_0729_112557_065.JPG_15f07152-76d0-4834-993b-2ca8f589310f.JPG -> 2018_0729_112557_065_1.JPG
output_original_2018_0729_112631_070.JPG_cd08da59-0de7-4a94-b769-5450fb80e982.JPG -> 2018_0729_112631_070.JPG
您可以使用bash patter替换和mv-backup=t重命名重复的文件名:
find . -name "output_original*" | while read -r file; do
origin=$file
file=${file/\.\/output_original_/}
file=${file/JPG*/JPG}
mv --backup=t $origin $file
done
样本输入:
find . -name "output*"
./output_original_2018_0729_112557_065.JPG_15f07152-76d0-4834-993b-2ca8f589310f.JPG
./output_original_2018_0729_112557_065.JPG_7c82d91a-6a2a-4f9f-a9ed-ccbc34afe7a9.JPG
./output_original_2018_0729_112631_070.JPG_cd08da59-0de7-4a94-b769-5450fb80e982.JPG
./output_original_2018_0729_112557_065.JPG_15f07152-76d0-4834-993b-2ca8f589310x.JPG
输出:
$find . -name "2018*"
./2018_0729_112557_065.JPG
./2018_0729_112557_065.JPG.~1~
./2018_0729_112557_065.JPG.~2~
./2018_0729_112631_070.JPG
您可以使用bash patter替换和mv-backup=t重命名重复的文件名:
find . -name "output_original*" | while read -r file; do
origin=$file
file=${file/\.\/output_original_/}
file=${file/JPG*/JPG}
mv --backup=t $origin $file
done
样本输入:
find . -name "output*"
./output_original_2018_0729_112557_065.JPG_15f07152-76d0-4834-993b-2ca8f589310f.JPG
./output_original_2018_0729_112557_065.JPG_7c82d91a-6a2a-4f9f-a9ed-ccbc34afe7a9.JPG
./output_original_2018_0729_112631_070.JPG_cd08da59-0de7-4a94-b769-5450fb80e982.JPG
./output_original_2018_0729_112557_065.JPG_15f07152-76d0-4834-993b-2ca8f589310x.JPG
输出:
$find . -name "2018*"
./2018_0729_112557_065.JPG
./2018_0729_112557_065.JPG.~1~
./2018_0729_112557_065.JPG.~2~
./2018_0729_112631_070.JPG
这将产生您想要的精确输出:
import os
import re
from collections import defaultdict
folder = "/path/to/out_original/folder"
regex = "output_original_(.+?.JPG)"
p = defaultdict(list)
for x in os.listdir(folder):
try:
p[re.findall(regex, x)[0]].append(x)
except:
pass
for k, v in p.items():
if len(v) == 1:
os.rename(os.path.join(folder, v[0]), os.path.join(folder, k))
else:
count = 1
for x in v:
os.rename(
os.path.join(folder, x),
os.path.join(folder, os.path.splitext(k)[0] + "_{}.JPG".format(count))
)
count += 1
这将产生您想要的精确输出:
import os
import re
from collections import defaultdict
folder = "/path/to/out_original/folder"
regex = "output_original_(.+?.JPG)"
p = defaultdict(list)
for x in os.listdir(folder):
try:
p[re.findall(regex, x)[0]].append(x)
except:
pass
for k, v in p.items():
if len(v) == 1:
os.rename(os.path.join(folder, v[0]), os.path.join(folder, k))
else:
count = 1
for x in v:
os.rename(
os.path.join(folder, x),
os.path.join(folder, os.path.splitext(k)[0] + "_{}.JPG".format(count))
)
count += 1
阐述@Sergio的想法:
# Make last also numbered
for file in *.JPG.~1~; do
cp --backup=numbered $file ${file/.~1~}
rm ${file/.~1~}
done
这将把2018_0729_112557_065.JPG变成2018_0729_112557_065.JPG.~3~
现在,要更改编号方案,请执行以下操作:
for file in *.JPG.~*~; do
new_name=$( echo "$file" | sed 's/\.JPG.~\([0-9]*\)~/_\1.JPG/'
mv "$file" "$new_name"; done
done
当然,如果你有.JPG以外的东西,你需要修改它。阐述@Sergio的想法:
# Make last also numbered
for file in *.JPG.~1~; do
cp --backup=numbered $file ${file/.~1~}
rm ${file/.~1~}
done
这将把2018_0729_112557_065.JPG变成2018_0729_112557_065.JPG.~3~
现在,要更改编号方案,请执行以下操作:
for file in *.JPG.~*~; do
new_name=$( echo "$file" | sed 's/\.JPG.~\([0-9]*\)~/_\1.JPG/'
mv "$file" "$new_name"; done
done
当然,如果你还有其他的.JPG,你需要修改它。是的,我在*中的文件中尝试了类似的方法;执行echo mv./$file./$echo$file |剪切-c17-;首先,对输出的原始字符串进行剪切。是的,我对*中的文件尝试了类似的操作;执行echo mv./$file./$echo$file |剪切-c17-;首先对输出的\u原始\u字符串进行剪切。这主意不错,但其中仍然没有计数器,如前一个答案。这主意不错,但其中仍然没有计数器,如前一个答案。刚刚尝试:回溯最近的调用上次:文件重命名\u names.py,第25行,在os.renamefilename中,新的\u文件名OSError:[Errno 2]没有这样的文件或目录刚刚试用过:回溯最近的调用last:file rename_names.py,第25行,在os.rename文件名中,新的文件名OSError:[Errno 2]没有这样的文件或目录这太棒了。谢谢!这太棒了。谢谢!