缩进中制表符和空格的使用不一致？？？（python）

我正在尝试制作一个石头、布、剪刀的游戏，尽管我的代码很好，但缩进错误中标签和空格的不一致使用还是出现了。 我该如何解决这个问题

我已经用notepad++、Visual Studio和默认的python IDLE重新编写了代码

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任何帮助都将不胜感激。

对于同一级别的if/elif/else语句，您的选项卡应该保持一致。我猜您可能希望将代码重新格式化为以下格式：

if ai == 1 and rock == True:

     lblr = tkinter.Label(menuwol, text="Neither win, the both of you picked rocks.")
     time.sleep(1)
     menuwol.destroy()
     lblr.pack()

elif ai == 1 and paper == True:

    lblr = tkinter.Label(menuwol, text="Computer picked rock, you picked paper, you win!")
    time.sleep(1)
    menuwol.destroy()
    lblr.pack()

elif ai == 1 and sissors == True:

    lblr = tkinter.Label(menuwol, text="Computer picked rock, you picked sissors, computer wins!")
    time.sleep(1)
    menuwol.destroy()
    lblr.pack()

elif ai == 2 and rock == True:

    lblr = tkinter.Label(menuwol, text="Computer picked paper, you picked rock, computer wins!")
    time.sleep(1)
    menuwol.destroy()
    lblr.pack()

elif ai == 2 and paper == True:

    lblr = tkinter.Label(menuwol, text="Neither win, both of you picked paper.")
    time.sleep(1)
    menuwol.destroy()
    lblr.pack()

elif ai == 2 and sissors == True:

    lblr = tkinter.Label(menuwol, text="Computer picked paper, you picked sissors, you win!")
    time.sleep(1)
    menuwol.destroy()
    lblr.pack()

elif ai == 3 and rock == True:

    lblr = tkinter.Label(menuwol, text="Computer picked sissors, you picked rock, you win!")
    time.sleep(1)
    menuwol.destroy()
    lblr.pack()

elif ai == 3 and paper == True:

    lblr = tkinter.Label(menuwol, text="Computer picked sissors, you picked paper, computer wins!")
    time.sleep(1)
    menuwol.destroy()
    lblr.pack()

elif ai == 3 and sissors == True:

    lblr = tkinter.Label(menuwol, text="Neither win, both of you picked sissors.")
    time.sleep(1)
    menuwol.destroy()
    lblr.pack()

else:

    lblr = tkinter.Label(menuwol, text="Error BOIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII!!!")
    time.sleep(1)
    menuwol.destroy()
    lblr.pack()

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如果这是您的代码，它不好，则

elif

s应与第一个

if

您的代码不好对齐，至少不像这里显示的那样。错误非常明显：缩进中有空格和制表符；用另一个替换所有代码，并修复编辑器以一致地使用空格（推荐）。“我的代码可能不正确吗？”对于任何版本的Python，该代码的缩进都不正确，但我认为在这里复制代码只是一个意外。出现这个错误消息是因为缩进Python3代码时不能混合制表符和空格，就这么简单。

if ai == 1 and rock == True:
    lblr = tkinter.Label(menuwol, text="Neither win, the both of you picked rocks.")
    time.sleep(1)
    menuwol.destroy()

elif ai == 1 and paper == True:

    lblr = tkinter.Label(menuwol, text="Computer picked rocks, you picked paper, you win!")
    time.sleep(1)
    menuwol.destroy()

elif ai == 1 and sissors == True:

    lblr = tkinter.Label(menuwol, text="Computer picked rocks, you picked sissors, computer wins!")
    time.sleep(1)
    menuwol.destroy()

elif ai == 2 and rock == True:

    lblr = tkinter.Label(menuwol, text="Computer picked paper, you picked rocks, computer wins!")
    time.sleep(1)
    menuwol.destroy()
    #rest of code