Python 要将列表转换为字符串，请参见下面的示例

我从一列

df['Test']中得到一个结果集。head（）

：

我希望将其转换为以下格式，并存储在与以下格式相同的列中：

fed official say weak data caused weather slow taper
fed 's Charles plosser see high bar change pace tapering

使用

.apply（“.join）

Ex:

import pandas  as pd

df = pd.DataFrame({'Test': [['fed', 'official', 'say', 'weak', 'data', 'caused', 'weather', 'slow', 'taper'],
                            ['fed', "'s", 'charles', 'plosser', 'see', 'high', 'bar', 'change', 'pace', 'tapering']
                           ]
                })
print(df["Test"].apply(" ".join))

0    fed official say weak data caused weather slow...
1    fed 's charles plosser see high bar change pac...
Name: Test, dtype: object

>>> import pandas as pd

>>> df = pd.DataFrame({'Test': ["[fed, official, say, weak, data, caused, weather, slow, taper]",
                            "[fed, 's, charles, plosser, see, high, bar, change, pace, tapering]"
                           ]
                })

>>> df['Test']=df['Test'].str[1:-1].str.split(', ').apply(' '.join)

>>> df
                                                Test
0  fed official say weak data caused weather slow...
1  fed 's charles plosser see high bar change pac...

输出：

import pandas  as pd

df = pd.DataFrame({'Test': [['fed', 'official', 'say', 'weak', 'data', 'caused', 'weather', 'slow', 'taper'],
                            ['fed', "'s", 'charles', 'plosser', 'see', 'high', 'bar', 'change', 'pace', 'tapering']
                           ]
                })
print(df["Test"].apply(" ".join))

0    fed official say weak data caused weather slow...
1    fed 's charles plosser see high bar change pac...
Name: Test, dtype: object

>>> import pandas as pd

>>> df = pd.DataFrame({'Test': ["[fed, official, say, weak, data, caused, weather, slow, taper]",
                            "[fed, 's, charles, plosser, see, high, bar, change, pace, tapering]"
                           ]
                })

>>> df['Test']=df['Test'].str[1:-1].str.split(', ').apply(' '.join)

>>> df
                                                Test
0  fed official say weak data caused weather slow...
1  fed 's charles plosser see high bar change pac...

---

由于您的列表格式不正确

首先我转换成单词列表，然后转换成字符串

代码：

import pandas  as pd

df = pd.DataFrame({'Test': [['fed', 'official', 'say', 'weak', 'data', 'caused', 'weather', 'slow', 'taper'],
                            ['fed', "'s", 'charles', 'plosser', 'see', 'high', 'bar', 'change', 'pace', 'tapering']
                           ]
                })
print(df["Test"].apply(" ".join))

0    fed official say weak data caused weather slow...
1    fed 's charles plosser see high bar change pac...
Name: Test, dtype: object

>>> import pandas as pd

>>> df = pd.DataFrame({'Test': ["[fed, official, say, weak, data, caused, weather, slow, taper]",
                            "[fed, 's, charles, plosser, see, high, bar, change, pace, tapering]"
                           ]
                })

>>> df['Test']=df['Test'].str[1:-1].str.split(', ').apply(' '.join)

>>> df
                                                Test
0  fed official say weak data caused weather slow...
1  fed 's charles plosser see high bar change pac...

输出：

import pandas  as pd

df = pd.DataFrame({'Test': [['fed', 'official', 'say', 'weak', 'data', 'caused', 'weather', 'slow', 'taper'],
                            ['fed', "'s", 'charles', 'plosser', 'see', 'high', 'bar', 'change', 'pace', 'tapering']
                           ]
                })
print(df["Test"].apply(" ".join))

0    fed official say weak data caused weather slow...
1    fed 's charles plosser see high bar change pac...
Name: Test, dtype: object

>>> import pandas as pd

>>> df = pd.DataFrame({'Test': ["[fed, official, say, weak, data, caused, weather, slow, taper]",
                            "[fed, 's, charles, plosser, see, high, bar, change, pace, tapering]"
                           ]
                })

>>> df['Test']=df['Test'].str[1:-1].str.split(', ').apply(' '.join)

>>> df
                                                Test
0  fed official say weak data caused weather slow...
1  fed 's charles plosser see high bar change pac...

试试这个：

for index, row in df.iterrows() : 
  s = ''
  for i in row['Test'] : 
    s = s + i
  df['Test'][index] = s

---

谢谢你们的帮助

df['Test'].apply（lambda x:：.join（[Word（Word）.lemmatize（）表示x.split（）中的单词））

---

它在上述场景中起作用。

您是否尝试在数据帧的每一行上使用

'.join（）

？尝试了，但出现了错误'，'。join（s）错误-名称“fed”未定义您已经尝试了什么？我们是来帮忙的，不是为你做的；）列表中的数据应为数据类型字符串，即用引号括起来，如

“data”

。所以，把你的清单列成这样-

[“联邦储备银行”，“官方”，…]

。你能告诉我们你已经尝试了什么吗。我尝试使用df['Test'].apply（lambda x:“”.join（[Word（Word）.lemmatize（）表示x.split（）中的单词））