Python-如何使用csv.writer而不使用引号

我有一个列表，其中的内容必须写入csv文件，没有报价

清单内容如下：

list=[(1, 2, 1), (1, 3, 1), (1, 4, 1), (1, 5, 1), (2, 1, 1), (2, 3, 1), (2, 4, 1), (2, 5, 1), (3, 1, 1), (3, 2, 1), (3, 4, 1), (3, 5, 1), (4, 1, 1), (4, 2, 1), (4, 3, 1), (4, 5, 1), (5, 1, 1), (5, 2, 1), (5, 3, 1), (5, 4, 1)]

(1,, 2,, 1),(1,, 3,, 1),(1,, 4,, 1),(1,, 5,, 1),(2,, 1,, 1),(2,, 3,, 1),(2,, 4,, 1),(2,, 5,, 1),(3,, 1,, 1),(3,, 2,, 1),(3,, 4,, 1),(3,, 5,, 1),(4,, 1,, 1),(4,, 2,, 1),(4,, 3,, 1),(4,, 5,, 1),(5,, 1,, 1),(5,, 2,, 1),(5,, 3,, 1),(5,, 4,, 1)

现在，我有以下两个代码段，试图将此列表写入csv文件：

方法1：

定义方法1：

list=[(1, 2, 1), (1, 3, 1), (1, 4, 1), (1, 5, 1), (2, 1, 1), (2, 3, 1), (2, 4, 1), (2, 5, 1), (3, 1, 1), (3, 2, 1), (3, 4, 1), (3, 5, 1), (4, 1, 1), (4, 2, 1), (4, 3, 1), (4, 5, 1), (5, 1, 1), (5, 2, 1), (5, 3, 1), (5, 4, 1)]
myfile = open('output.csv', 'w')
        wr = csv.writer(myfile, quoting = csv.QUOTE_NONE, delimiter=',', escapechar=',')
        wr.writerow(list)

csv文件的内容如下所示：

list=[(1, 2, 1), (1, 3, 1), (1, 4, 1), (1, 5, 1), (2, 1, 1), (2, 3, 1), (2, 4, 1), (2, 5, 1), (3, 1, 1), (3, 2, 1), (3, 4, 1), (3, 5, 1), (4, 1, 1), (4, 2, 1), (4, 3, 1), (4, 5, 1), (5, 1, 1), (5, 2, 1), (5, 3, 1), (5, 4, 1)]

(1,, 2,, 1),(1,, 3,, 1),(1,, 4,, 1),(1,, 5,, 1),(2,, 1,, 1),(2,, 3,, 1),(2,, 4,, 1),(2,, 5,, 1),(3,, 1,, 1),(3,, 2,, 1),(3,, 4,, 1),(3,, 5,, 1),(4,, 1,, 1),(4,, 2,, 1),(4,, 3,, 1),(4,, 5,, 1),(5,, 1,, 1),(5,, 2,, 1),(5,, 3,, 1),(5,, 4,, 1)

我不希望，在列表的元素之间。如果我从上述代码中删除escapechar，它将抛出一个错误

错误是：

_csv.错误：需要转义，但未设置转义

方法2：

定义方法2：

list=[(1, 2, 1), (1, 3, 1), (1, 4, 1), (1, 5, 1), (2, 1, 1), (2, 3, 1), (2, 4, 1), (2, 5, 1), (3, 1, 1), (3, 2, 1), (3, 4, 1), (3, 5, 1), (4, 1, 1), (4, 2, 1), (4, 3, 1), (4, 5, 1), (5, 1, 1), (5, 2, 1), (5, 3, 1), (5, 4, 1)]
myfile = open('output.csv', 'wb')
        wr = csv.writer(myfile)
        wr.writerow(list)

方法2的输出如下图所示：

list=[(1, 2, 1), (1, 3, 1), (1, 4, 1), (1, 5, 1), (2, 1, 1), (2, 3, 1), (2, 4, 1), (2, 5, 1), (3, 1, 1), (3, 2, 1), (3, 4, 1), (3, 5, 1), (4, 1, 1), (4, 2, 1), (4, 3, 1), (4, 5, 1), (5, 1, 1), (5, 2, 1), (5, 3, 1), (5, 4, 1)]

(1,, 2,, 1),(1,, 3,, 1),(1,, 4,, 1),(1,, 5,, 1),(2,, 1,, 1),(2,, 3,, 1),(2,, 4,, 1),(2,, 5,, 1),(3,, 1,, 1),(3,, 2,, 1),(3,, 4,, 1),(3,, 5,, 1),(4,, 1,, 1),(4,, 2,, 1),(4,, 3,, 1),(4,, 5,, 1),(5,, 1,, 1),(5,, 2,, 1),(5,, 3,, 1),(5,, 4,, 1)

1,2,1,1,1,3,1,1,4,1,1,1,5,1,2,3,1,2,4,1,2,1,2,1,3,1,3,2,1,3,4,4,1,1,4,2,1,4,3,1,4,5,1,5,1,2,5,3,1,5,1,5,1,5,4,1

有人能帮我解决这个问题吗

我的输出文件的内容必须如下所示：

(1, 2, 1), 
(1, 3, 1), 
(1, 4, 1), 
(1, 5, 1),

...
...

list=[(1, 2, 1), (1, 3, 1), (1, 4, 1), (1, 5, 1), (2, 1, 1), (2, 3, 1), (2, 4, 1), (2, 5, 1), (3, 1, 1), (3, 2, 1), (3, 4, 1), (3, 5, 1), (4, 1, 1), (4, 2, 1), (4, 3, 1), (4, 5, 1), (5, 1, 1), (5, 2, 1), (5, 3, 1), (5, 4, 1)]

with open("output.csv", "w") as out_f:
    for item in list:
        output_str = "{},\n".format(item)
        out_f.write(output_str)

---

您根本不需要csv，请看以下内容：

>>> list=[(1, 2, 1), (1, 3, 1), (1, 4, 1), (1, 5, 1), (2, 1, 1), (2, 3, 1), (2, 4, 1), (2, 5, 1), (3, 1, 1), (3, 2, 1), (3, 4, 1), (3, 5, 1), (4, 1, 1), (4, 2, 1), (4, 3, 1), (4, 5, 1), (5, 1, 1), (5, 2, 1), (5, 3, 1), (5, 4, 1)]
>>> with open('out.txt', 'w') as out:
...     for t in list:
...         out.write(str(t)+",\n")
... 
>>> 
host:~$ head out.txt 
(1, 2, 1),
(1, 3, 1),
(1, 4, 1),
(1, 5, 1),
(2, 1, 1),
(2, 3, 1),
(2, 4, 1),
(2, 5, 1),
(3, 1, 1),
(3, 2, 1),

---

您描述的格式似乎不需要csv模块。您可以使用以下方式写出格式：

(1, 2, 1), 
(1, 3, 1), 
(1, 4, 1), 
(1, 5, 1),

...
...

list=[(1, 2, 1), (1, 3, 1), (1, 4, 1), (1, 5, 1), (2, 1, 1), (2, 3, 1), (2, 4, 1), (2, 5, 1), (3, 1, 1), (3, 2, 1), (3, 4, 1), (3, 5, 1), (4, 1, 1), (4, 2, 1), (4, 3, 1), (4, 5, 1), (5, 1, 1), (5, 2, 1), (5, 3, 1), (5, 4, 1)]

with open("output.csv", "w") as out_f:
    for item in list:
        output_str = "{},\n".format(item)
        out_f.write(output_str)

---

如果这是您的输出格式，我看不出使用csv模块有什么好处。@monkut您能告诉我怎么做吗？太好了，谢谢您的快速回复！还有一个问题，你能告诉我什么时候需要使用csv模块，什么时候不需要吗？考虑到上述情况，我挣扎了很多！