Python 索引器：由于i'；我改变了文件的读取方式

我正在尝试读取并重新格式化一个非常大的（2GB+）.out文件，该文件的结构类似于csv。我以前使用过标准的open（），但没有这样的问题，但将其改为codecs.open（），因为它在某些字符方面有问题

它现在正在投掷

回溯（最近一次呼叫最后一次）：
第21行，在
如果（r[5]==”）：
索引器：在第一行列出索引超出范围

，尽管在r[5]处肯定有一个元素。 （运行时间为0.301s）

导入系统 导入csv 导入日期时间 导入编解码器 maxInt=sys.maxsize 减量=真 减量化： 减量=假 尝试： csv.字段大小限制（maxInt） 除溢出错误外： maxInt=int（maxInt/10） 减量=真 以codecs.open（“file.out”、“rU”、“utf-16-be”）作为源： rdr=csv.reader（源） 打开（“out.csv”，“w”，换行符=”）作为结果： wtr=csv.writer（结果） wtr.writerow（（“第1列”、“第2列”、“第3列”、“等”） 对于rdr中的r： 如果（r[5]==”）： 持续 wtr.writerow（（datetime.datetime.strtime（r[5]，“%m/%d/%Y”）.strftime（“%Y-%m-%d”）、r[3]、r[7]、r[9]+r[10]+“”+r[12]）） 使用utf-8抛出UnicodeDecodeError:“utf-8”编解码器无法解码位置12处的字节0xc9：无效的连续字节

使用latin-1或ISO-8859-1抛出UnicodeEncodeError:“charmap”编解码器无法对位置57-58中的字符进行编码：字符映射到，尽管运行了更多

输入文件如下所示：

"A00017","K","G","1999","4530","01/12/1999","","","","PEOPLE TO ELECT MANGINELLI","","","","258 MAGNIOLIA DRIVE","SELDEN","NY","11784","","","404.57","","","","","","","2","","NAA","07/22/1999 08:43:59"
"A00037","K","G","1999","999999","01/12/1999","","","","CITIZENS TO ELECT TEDISCO TO ASSEMBLY","","","","","","","","","","0","","","","","","","2","","",""
"A00037","K","N","1999","1693","01/15/1999","","","","OUTSTANDING LOAN","","","","2176 GUILDERLAND AVE","SCHENECTADY","NY","12306","","","10474.8","10474.8","","","OTHER","","PREVIOUS LOAN FROM JAMES TEDISCO","","P","JM","07/15/1999 15:08:17"
"A00037","J","N","2000","1694","01/13/2000","","","","OUTSTANDING LOAN","","","","2176 GUILDERLAND","SCHENECTADY","NY","12306","","","10474.8","10474.8","","","OTHER","","LOANS FROM PREVIOUS CAMPAIGNS FROM J","","P","JM","01/14/1900 16:35:09"
"A00037","K","X","2000","999999","","","","","","","","","","","","","","","","","","","","","","","","","07/20/2000 00:00:00"
"A00037","J","X","2001","999999","","","","","","","","","","","","","","","","","","","","","","","","","01/17/2001 00:00:00"
"A00037","K","X","2002","999999","","","","","","","","","","","","","","","","","","","","","","","","","07/19/2002 00:00:00"
"A00037","J","X","2003","999999","","","","","","","","","","","","","","","","","","","","","","","","","01/21/2003 00:00:00"
"A00037","K","X","2003","999999","","","","","","","","","","","","","","","","","","","","","","","","","07/16/2003 00:00:00"
"A00037","J","X","2004","999999","","","","","","","","","","","","","","","","","","","","","","","","","01/22/2004 00:00:00"

我走到今天多亏了：

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在正在读取的“file.out”中，找出行中每个单元格元素之间的分隔字符。类似于“\t”-制表符或“，”-逗号，并将其传递给“delimiter”属性

尝试打印“r”，并查看列名或行中值之间的字符

rdr = csv.reader(source,delimiter=<separator>)

rdr=csv.reader（源代码，分隔符=）

能否在循环中打印

r

？而不必看到重现问题的文件，我们很难帮助您。您是否尝试过打印“r”并查看它是否是数组？尝试过将r打印到控制台并得到

UnicodeEncodeError:“charmap”编解码器无法对位置2-97中的字符进行编码：字符映射到

在编解码器中使用“utf-8”。打开（“file.out”，“rU”，“utf-8”）您是否可以尝试使用“latin-1”或“ISO-8859-1”编码而不是“utf-8”您是否可以尝试以下代码：rdr=csv.reader（（line.replace（'\0'，''）表示源代码中的行），delimiter='，'）。您是否可以共享导致错误的数据中的行