Python3获取子元素（lxml）

我将lxml与html一起使用：

from lxml import html
import requests

如何检查元素的任何子元素是否具有class=“nearly” 我的代码（基本上）：

如何替换“HasChildWithClass（）”使其实际工作

下面是一个示例树：

...
    <p class="result-info">
        <span class="result-meta">
            <span class="nearby">
                ... #this SHOULD print something
            </span>
        </span>
    </p>
    <p class="result-info">
        <span class="result-meta">
            <span class="FAR-AWAY">
                ... # this should NOT print anything
            </span>
        </span>
    </p>
...

。。。

... #这应该会打印一些东西


... # 这不应该打印任何内容

...

这是我做的一个实验

在python shell中获取

r=resultList[0]

，然后键入：

>>> dir(r)
['__bool__', '__class__', ..., 'find_class', ...

现在这个

find_class

方法非常可疑。如果您查看其帮助文档：

>>> help(r.find_class)

你会证实这个猜测的。的确

>>> r.find_class('nearby')
[<Element span at 0x109788ea8>]

现在，如何判断“附近”的孩子是否存在已经很清楚了

---

干杯

我试图理解为什么要使用

lxml

来查找元素。但是，

BeautifulSoup

和

re

可能是更好的选择

lxml = """
    <p class="result-info">
        <span class="result-meta">
            <span class="nearby">
                ... #this SHOULD print something
            </span>
        </span>
    </p>
    <p class="result-info">
        <span class="result-meta">
            <span class="FAR-AWAY">
                ... # this should NOT print anything
            </span>
        </span>
    </p>
    """

尝试使用

bs4

from bs4 import BeautifulSoup


soup = BeautifulSoup(lxml,"lxml")
result = soup.find_all("span", class_="nearby")
print(result[0].text)

lxml = """
    <p class="result-info">
        <span class="result-meta">
            <span class="nearby">
                ... #this SHOULD print something
            </span>
        </span>
    </p>
    <p class="result-info">
        <span class="result-meta">
            <span class="FAR-AWAY">
                ... # this should NOT print anything
            </span>
        </span>
    </p>
    """

from lxml import html

Tree = html.fromstring(lxml)
resultList = Tree.xpath('//p[@class="result-info"]')
i = len(resultList) - 1 #to go though the list backwards
for result in resultList:
    for e in result.iter():
        if e.attrib.get("class") == "nearby":
            print(e.text)

from bs4 import BeautifulSoup


soup = BeautifulSoup(lxml,"lxml")
result = soup.find_all("span", class_="nearby")
print(result[0].text)