Python-如何排除Sat和Sun。从几周开始

我希望有人能给我举一些例子，说明我可以返回日历数据的方法

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返回任何给定月份（过去/现在/将来）的天数， 但不包括周六和周日 示例：

输入（'Year:'）-2018

输入（'月份：'）-7

最终结果：2018年7月的工作日数为（22）

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排除周六和周日后，为每个工作日分配一个迭代器

示例：

输入（'Year:'）-2018

输入（'月份：'）-7

输入（'日期：'）-20

最终结果：这（20）是一个（周五），是（2018年7月）的（15）工作日

这是我到目前为止能够创建的代码

import calendar

year = float(input('Year: '))
month = float(input('Month: '))
input_year = []
input_month = []

if year >= 1000 and year <=3000:
    input_year.append(year)
if month >= 1 and month <=12:
    input_month.append(month)

cal_format = calendar.TextCalendar(calendar.MONDAY)
result_cal = cal_format.formatmonth(int(input_year[0]), int(input_month[0]))
print(result_cal)

THE END RESULT IS...

Year: 1978
Month: 3
     March 1978
Mo Tu We Th Fr Sa Su
       1  2  3  4  5
 6  7  8  9 10 11 12
13 14 15 16 17 18 19
20 21 22 23 24 25 26
27 28 29 30 31

导入日历
年份=浮动（输入（'年份：'））
月份=浮动（输入（'月份：'））
输入年份=[]
输入月份=[]
如果年>=1000，年=1，月获取一个月内的工作日数：

import calendar

weekdays = 0
cal = calendar.Calendar()

for week in cal.monthdayscalendar(2018, 7):
    for i, day in enumerate(week):
        # Check if is a weekday and the day is from this month
        if i < 5 and day != 0:
            weekdays += 1

print weekdays

导入日历
工作日=0
cal=calendar.calendar（）
对于cal.monthdayscalendar的一周（2018年7月）：
对于i，枚举中的天（周）：
#检查是否为工作日，日期是否从本月开始
如果我<5天！=0:
工作日+=1
打印工作日

要获取特定日期的工作日数，可以修改上述代码，以在到达输入日期时返回工作日计数
 这里有一种方法可以找到以前工作日的数量：

请注意，年、月、日的类型转换为
int

import calendar

year = int(input('Year: '))
month = int(input('Month: '))
day = int(input('Day: '))

full_wks = day / 7
extra_days = day % 7

first_day = calendar.weekday(year, month, 1)
if first_day >= 5:              # if month begins on a weekend
    weekend = 7 - first_day     # yields 1 if Sunday, 2 if Saturday
    extra_days -= weekend

weekdays = full_wks * 5 + extra_days

ordinal = lambda n: "{}{}".format(n, 'tsnrhtdd'[n%5*(n%100^15>4>n%10)::4])

print "{}/{} is the {} weekday in the month.".format(month, day, ordinal(weekdays))

输出：

Year: 2018
Month: 7
Day: 20
7/20 is the 15th weekday in the month.

从xsot开始的序号转换。
检查日期工作日的一种方法是使用
日期
对象的方法。它位于python标准库
datetime
模块中

日期.工作日（）

以整数形式返回一周中的某一天，其中周一为0，周日为6。例如，
date（2002，12，4）.weekday（）==2
，一个星期三。另见

导入日期时间
工作日的数量=0
工作日列表=[]
开始日期=datetime.date（int（输入年份[0]），int（输入月份[0]），1）
当前日期=开始日期
当cur_date.month==start_date.month时：
如果010分钟左右，我做了一个简单的溶液。我的方法在很大程度上依赖于列表理解和字符串方法，如join和split，因此如果您还不熟悉它们，我建议您查找它们。首先将结果分成几行，标题需要重新居中，其他行需要删除最后的字符

使用strip（）方法重新居中第一行，删除行间空白，然后预先添加两个空格

以周末为例，使用列表理解法只包括每行的前15个字符

最后一部分是最难的。我的想法是计算我的格式化日历中有多少天的数字。首先将所有带有日数的行放在一个大行中，然后将行按空格分割，得到一个包含所有日数的列表，最后使用列表的大小

import calendar

year = float(input('Year: '))
month = float(input('Month: '))
input_year = []
input_month = []

if year >= 1000 and year <=3000:
    input_year.append(year)
if month >= 1 and month <=12:
    input_month.append(month)

cal_format = calendar.TextCalendar(calendar.MONDAY)
result_cal = cal_format.formatmonth(int(input_year[0]), int(input_month[0]))

lines = result_cal.split("\n") # Split result_cal into a list of lines
title_line = lines[0] # Save first line, we want to edit this differently
title_line = "  " + title_line.strip() # Change the indentation of the title line


lines = lines[1:] # Now select lines below the first 
lines = [line[:3*5] for line in lines] # Only Keep first 15 characters or each
                                       # line to exclude weekends. (5 weekdays *
                                       # 3 chars per day)

lines = [line for line in lines if len(line.strip())] # Don't include empty lines
                                                      # happens if month starts
                                                      # on a weekend.

# prints out the result
print(title_line)
for line in lines:
    print(line)

# Next work out how many working days in month.
nums = "".join(lines[1:]).split(" ") # Three parts: first lines[1:] means this
                                     # only looks at the portion of the calendar
                                     # with numbers written on then. 2nd "".join()
                                     # joins the lines into a single string on 1 line
                                     # 3rd the .split(" ") splits the string based on spaces
                                     # unfortunatly 2 consecutive spaces result in an empty
                                     # string.

nums = [num for num in nums if len(num)] # Filters the empty string.
print(f"There are {len(nums)} working days in the month you selected") # Prints result
#(uses f-string, you may want to look them up, I find them to be very useful)

导入日历
年份=浮动（输入（'年份：'））
月份=浮动（输入（'月份：'））
输入年份=[]
输入月份=[]
如果年份>=1000，年份=1，月份
import calendar

year = float(input('Year: '))
month = float(input('Month: '))
input_year = []
input_month = []

if year >= 1000 and year <=3000:
    input_year.append(year)
if month >= 1 and month <=12:
    input_month.append(month)

cal_format = calendar.TextCalendar(calendar.MONDAY)
result_cal = cal_format.formatmonth(int(input_year[0]), int(input_month[0]))

lines = result_cal.split("\n") # Split result_cal into a list of lines
title_line = lines[0] # Save first line, we want to edit this differently
title_line = "  " + title_line.strip() # Change the indentation of the title line


lines = lines[1:] # Now select lines below the first 
lines = [line[:3*5] for line in lines] # Only Keep first 15 characters or each
                                       # line to exclude weekends. (5 weekdays *
                                       # 3 chars per day)

lines = [line for line in lines if len(line.strip())] # Don't include empty lines
                                                      # happens if month starts
                                                      # on a weekend.

# prints out the result
print(title_line)
for line in lines:
    print(line)

# Next work out how many working days in month.
nums = "".join(lines[1:]).split(" ") # Three parts: first lines[1:] means this
                                     # only looks at the portion of the calendar
                                     # with numbers written on then. 2nd "".join()
                                     # joins the lines into a single string on 1 line
                                     # 3rd the .split(" ") splits the string based on spaces
                                     # unfortunatly 2 consecutive spaces result in an empty
                                     # string.

nums = [num for num in nums if len(num)] # Filters the empty string.
print(f"There are {len(nums)} working days in the month you selected") # Prints result
#(uses f-string, you may want to look them up, I find them to be very useful)