Python 按y轴旋转图像

我有一个函数

rotate

，它是通过y轴在输入角度上完美地旋转输入图像，但我面临一个问题。输出图像的角被裁剪，我认为图像边界有问题，但我不确定。 我的职能

import numpy as np
import cv2
import math


def rotate_y(img, y):
    # change size of image
    width = img.shape[1]
    height = img.shape[0]

    # 2d to 3d (projection)  , and -> rotation point - center point (origin point)
    proj2dto3d = np.array([[1, 0, -img.shape[1] / 2],
                           [0, 1, -img.shape[0] / 2],
                           [0, 0, 0],
                           [0, 0, 1]], np.float32)

    # 3d matrix in  y
    ry = np.array([[1, 0, 0, 0],
                   [0, 1, 0, 0],
                   [0, 0, 1, 0],
                   [0, 0, 0, 1]], np.float32)


    trans = np.array([[1, 0, 0, 0],
                      [0, 1, 0, 0],
                      [0, 0, 1, 100], 
                      [0, 0, 0, 1]], np.float32)

    proj3dto2d = np.array([[100, 0, img.shape[1] / 2, 0],
                           [0, 100, img.shape[0] / 2, 0],
                           [0, 0, 1, 0]], np.float32)

    ay = float(y * (math.pi / 180))

    ry[0, 0] = math.cos(ay)
    ry[0, 2] = -math.sin(ay)
    ry[2, 0] = math.sin(ay)
    ry[2, 2] = math.cos(ay)

    final = proj3dto2d.dot(trans.dot(ry.dot(proj2dto3d)))

    # rotation calculates the cos and sin, taking absolutes of those.
    abs_cos = abs(math.cos(ay))
    abs_sin = abs(math.sin(ay))

    # find the new width and height bounds
    bound_w = int(height * abs_sin + width * abs_cos)
    bound_h = int(height * abs_cos + width * abs_sin)

    dst = cv2.warpPerspective(img, final, (bound_w, bound_h), None, cv2.INTER_LINEAR
                              , cv2.BORDER_CONSTANT, (0, 0, 0))
    return dst

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我想收到一张未剪切的图片。

请参见和@fmw42，是的，我已经阅读了这些文章，但只有关于x轴旋转的文章，我需要3d旋转（y轴）